Oxidation Examples in Chemistry
Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Oxidation.
This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Chemistry.
Concept Recap
The loss of electrons by an atom, ion, or molecule during a chemical reaction, resulting in an increase in its oxidation state. Oxidation always occurs simultaneously with reduction in a redox pair.
Giving away electrons. Originally meant 'gaining oxygen' but it's broader.
Read the full concept explanation โHow to Use These Examples
- Read the first worked example with the solution open so the structure is clear.
- Try the practice problems before revealing each solution.
- Use the related concepts and background knowledge badges if you feel stuck.
What to Focus On
Core idea: OIL RIG: Oxidation Is Loss of electrons โ always paired with reduction in a redox reaction.
Common stuck point: Oxidation doesn't require oxygen โ it's defined by electron loss, not by reacting with oxygen gas.
Sense of Study hint: When identifying oxidation in a reaction, track electron movement. First assign oxidation numbers to each atom before and after the reaction. Then find which atoms increased in oxidation number โ those were oxidized. Finally, remember OIL RIG: Oxidation Is Loss of electrons.
Worked Examples
Example 1
easySolution
- 1 Mg goes from oxidation state 0 (element) to +2 (in MgO).
- 2 An increase in oxidation number means the species has lost electrons.
- 3 Therefore, Mg is oxidized: \text{Mg} \rightarrow \text{Mg}^{2+} + 2e^-.
Answer
Example 2
mediumPractice Problems
Try these problems on your own first, then open the solution to compare your method.
Example 1
easyExample 2
mediumRelated Concepts
Background Knowledge
These ideas may be useful before you work through the harder examples.