Molar Mass Chemistry Example 4

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Example 4

easy
What mass of calcium carbonate (CaCO3\text{CaCO}_3) is equal to 0.2500.250 mol? (Ca = 40.0840.08, C = 12.0112.01, O = 16.0016.00)

Solution

  1. 1
    Find the molar mass: 40.08+12.01+3(16.00)=100.09 g/mol40.08 + 12.01 + 3(16.00) = 100.09\,\text{g/mol}.
  2. 2
    Mass =n×M=0.250×100.09=25.0 g= n \times M = 0.250 \times 100.09 = 25.0\,\text{g}.

Answer

25.0 g of CaCO325.0\,\text{g of } \text{CaCO}_3
Molar mass tells you the mass of one mole. Once you know it, multiply by the number of moles to get the sample mass.

About Molar Mass

The mass in grams of exactly one mole of a substance, calculated by summing the atomic masses of all atoms in the chemical formula.

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More Molar Mass Examples

Example 1 easy

Calculate the molar mass of glucose ([formula]).

Example 2 medium

What mass of calcium chloride ([formula]) contains [formula] mol? (Ca = 40.08, Cl = 35.45 g/mol)

Example 3 easy

Calculate the molar mass of sulfuric acid ([formula]). (H = 1.008, S = 32.07, O = 16.00)

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