Gas Laws Chemistry Example 2

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Example 2

medium
Use the ideal gas law to find the volume occupied by 2.02.0 mol of gas at 25Β°C25Β°\text{C} and 1.0 atm1.0\,\text{atm}. (R=0.0821 L\cdotpatm/mol\cdotpKR = 0.0821\,\text{LΒ·atm/molΒ·K})

Solution

  1. 1
    Convert temperature: T=25+273=298 KT = 25 + 273 = 298\,\text{K}.
  2. 2
    Use PV=nRTPV = nRT: V=nRTP=2.0Γ—0.0821Γ—2981.0V = \frac{nRT}{P} = \frac{2.0 \times 0.0821 \times 298}{1.0}.
  3. 3
    V=48.931.0=48.9 LV = \frac{48.93}{1.0} = 48.9\,\text{L}.

Answer

V=48.9 LV = 48.9\,\text{L}
The ideal gas law PV=nRTPV = nRT unifies all the individual gas laws (Boyle's, Charles's, Avogadro's) into one equation. Always convert temperature to Kelvin.

About Gas Laws

A set of mathematical relationships that describe how the pressure, volume, temperature, and amount (moles) of a gas are interconnected.

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