Empirical Formula Examples in Chemistry
Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Empirical Formula.
This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Chemistry.
Concept Recap
The simplest whole-number ratio of atoms of each element present in a compound, found by reducing the actual atom counts.
The reduced fraction of atomsβsmallest numbers that show the ratio.
Read the full concept explanation βHow to Use These Examples
- Read the first worked example with the solution open so the structure is clear.
- Try the practice problems before revealing each solution.
- Use the related concepts and background knowledge badges if you feel stuck.
What to Focus On
Core idea: Shows the ratio of elements, not the actual number of atoms per molecule.
Common stuck point: Different compounds can share the same empirical formula β glucose and acetic acid both give CHβO.
Worked Examples
Example 1
mediumSolution
- 1 Assume 100 g: C = 40.0 g, H = 6.7 g, O = 53.3 g.
- 2 Convert to moles: C = \frac{40.0}{12.01} = 3.33, H = \frac{6.7}{1.008} = 6.65, O = \frac{53.3}{16.00} = 3.33.
- 3 Divide by smallest (3.33): C = 1, H = 2, O = 1.
- 4 Empirical formula: \text{CH}_2\text{O}.
Answer
Example 2
hardPractice Problems
Try these problems on your own first, then open the solution to compare your method.
Example 1
mediumExample 2
mediumRelated Concepts
Background Knowledge
These ideas may be useful before you work through the harder examples.