Actual Yield Examples in Chemistry

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Actual Yield.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Chemistry.

Concept Recap

The amount of product actually obtained from a reaction in the lab or in an industrial process.

What you really got after doing the reaction.

Read the full concept explanation →

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Actual Yield starts with the given amount, names the substance, and chooses the conversion factor that cancels the old unit.

Common stuck point: Students often know a formula related to actual yield but skip the recognition step: Am I using a mole bridge, molar mass, formula ratio, or balanced-equation ratio to connect measured amounts? That leads to a correct-looking substitution attached to the wrong chemical model.

Sense of Study hint: Ask: Am I using a mole bridge, molar mass, formula ratio, or balanced-equation ratio to connect measured amounts?

Worked Examples

Example 1

medium
A chemist predicts 50 g50\text{ g} of aspirin from a synthesis but isolates 40 g40\text{ g} after purification. Walk through finding (a) actual yield and (b) percent yield.

Answer

actual=40 g, percent yield=80%\text{actual} = 40\text{ g},\ \text{percent yield} = 80\%

First step

1
Actual yield is the measured isolated product: 40 g40\text{ g}.

See the full worked solution + why-it-works coaching

SetupKey insightWhy it worksCommon pitfallConnection

Unlock answer keys One Family plan — every worked solution, all subjects

Example 2

medium
For 2H2+O22H2O2H_2 + O_2 \rightarrow 2H_2O, 0.60 mol0.60\text{ mol} H2H_2 (excess O2O_2) gives an actual 9.0 g9.0\text{ g} of water (M=18M=18). Find theoretical mass and percent yield.

Example 3

medium
CaCO3CaO+CO2CaCO_3 \rightarrow CaO + CO_2. A student heats 20.0 g20.0\text{ g} CaCO3CaCO_3 (M=100M=100) and weighs 9.52 g9.52\text{ g} CaOCaO (M=56M=56). Find percent yield.

Example 4

hard
4Fe+3O22Fe2O34Fe + 3O_2 \rightarrow 2Fe_2O_3. Burning 11.2 g11.2\text{ g} Fe (M=56M=56) in excess oxygen gives 14.4 g14.4\text{ g} Fe2O3Fe_2O_3 (M=160M=160). Find percent yield.

Example 5

hard
2KClO32KCl+3O22KClO_3 \rightarrow 2KCl + 3O_2. Heating 24.5 g24.5\text{ g} KClO3KClO_3 (M=122.5M=122.5) gives 8.64 g8.64\text{ g} O2O_2 (M=32M=32). Find percent yield.

Example 6

hard
AgNO3+NaClAgCl+NaNO3AgNO_3 + NaCl \rightarrow AgCl + NaNO_3. Mixing 0.100 mol0.100\text{ mol} AgNO3AgNO_3 with excess NaClNaCl yields 12.9 g12.9\text{ g} AgClAgCl (M=143.5M=143.5). Compute percent yield.

Example 7

hard
Esterification predicts 0.40 mol0.40\text{ mol} ester. The student isolates 35.2 g35.2\text{ g} of ester (M=88 g/molM=88\text{ g/mol}). What is the percent yield?

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

medium
A reaction has theoretical yield 60 g60\text{ g} and actual yield 48 g48\text{ g}. What is the percent yield?

Example 2

easy
A reaction's theoretical yield is 50 g50\text{ g}, but a chemist measures 42 g42\text{ g} of product. What is the actual yield?

Example 3

easy
Is actual yield obtained by calculation or by measurement?

Example 4

easy
A lab recovers 18 g18\text{ g} of product from a reaction. If percent yield is 90%90\%, is 18 g18\text{ g} the actual or theoretical yield?

Example 5

easy
Can the actual yield ever exceed the theoretical yield in a pure reaction?

Example 6

easy
Theoretical yield is 80 g80\text{ g} and actual yield is 60 g60\text{ g}. How much product was lost?

Example 7

easy
A reaction gives an actual yield of 0 g0\text{ g} of the desired product. What does this indicate?

Example 8

easy
Which yield is used as the numerator in percent yield, actual or theoretical?

Example 9

easy
A student writes that the actual yield is 55 g55\text{ g} because that is what the balance read. Is this correct reasoning?

Example 10

medium
A reaction has theoretical yield 40 g40\text{ g}. The actual yield is 34 g34\text{ g}. What is the percent yield?

Example 11

medium
A reaction is expected to yield 25 g25\text{ g} product. If percent yield is 80%80\%, what is the actual yield?

Example 12

medium
2H2+O22H2O2H_2 + O_2 \rightarrow 2H_2O. From 4 mol4\text{ mol} H2H_2 (excess O2O_2), the theoretical yield of water is computed, but only 3 mol3\text{ mol} water forms. What is the actual yield in moles?

Example 13

medium
A process gives 90 g90\text{ g} actual yield at 75%75\% percent yield. What was the theoretical yield?

Example 14

medium
Theoretical yield is 0.50 mol0.50\text{ mol} product (M=60 g/molM=60\text{ g/mol}). The actual yield measured is 24 g24\text{ g}. What is the percent yield?

Example 15

medium
A reaction theoretically yields 10 g10\text{ g} but loses 30%30\% to side reactions. What actual yield is expected?

Example 16

medium
Two trials give actual yields of 18 g18\text{ g} and 22 g22\text{ g} for a reaction with theoretical yield 40 g40\text{ g}. What is the average percent yield?

Example 17

medium
A reaction's actual yield is 45 g45\text{ g} and percent yield is 90%90\%. By how many grams does the actual yield fall short of theoretical?

Example 18

challenge
CaCO3CaO+CO2CaCO_3 \rightarrow CaO + CO_2. Heating 100 g100\text{ g} CaCO3CaCO_3 (M=100M=100) gives 50 g50\text{ g} CaOCaO (M=56M=56) actual. Find percent yield.

Example 19

challenge
In N2+3H22NH3N_2 + 3H_2 \rightarrow 2NH_3, 1 mol1\text{ mol} N2N_2 with excess H2H_2 gives an actual yield of 25.5 g25.5\text{ g} NH3NH_3 (M=17M=17). Find percent yield.

Example 20

challenge
A two-step synthesis has 80%80\% yield in step 1 and 75%75\% in step 2. Starting from a theoretical 40 g40\text{ g}, what is the overall actual yield?

Example 21

easy
A reaction has theoretical yield 35 g35\text{ g} and actual yield 28 g28\text{ g}. What is the percent yield?

Example 22

easy
A student computes a theoretical yield of 44 g44\text{ g} and measures 33 g33\text{ g} on the balance. What is the actual yield?

Example 23

easy
Theoretical yield is 20 g20\text{ g} and actual yield is 15 g15\text{ g}. What percent yield is this?

Example 24

easy
A reaction yields 7.2 g7.2\text{ g} of product with a 90%90\% yield. Is 7.2 g7.2\text{ g} the actual or theoretical yield?

Example 25

easy
Theoretical yield is 120 g120\text{ g} and actual yield is 84 g84\text{ g}. What is the percent yield?

Example 26

medium
A reaction is predicted to give 0.40 mol0.40\text{ mol} of CO2CO_2 (M=44 g/molM=44\text{ g/mol}). The actual mass collected is 14.08 g14.08\text{ g}. Find the percent yield.

Example 27

medium
A reaction has a theoretical yield of 32 g32\text{ g} but loses 25%25\% of the product during workup. What is the actual yield?

Example 28

medium
A student gets an actual yield of 36 g36\text{ g} at a percent yield of 60%60\%. What was the theoretical yield?

Example 29

medium
Trial 1 gives actual yield 24 g24\text{ g}, trial 2 gives 26 g26\text{ g}, trial 3 gives 22 g22\text{ g}. If theoretical is 30 g30\text{ g}, what is the average percent yield across the three trials?

Example 30

medium
If 1.5 mol1.5\text{ mol} of product (M=40 g/molM=40\text{ g/mol}) is predicted and percent yield is 70%70\%, what mass is actually recovered?

Example 31

medium
A reaction has theoretical yield 0.25 mol0.25\text{ mol} and actual yield 0.20 mol0.20\text{ mol} (same product). What is the percent yield?

Example 32

medium
A reaction recovers 0.45 g0.45\text{ g} of product. If percent yield is 90%90\%, what is the theoretical yield in grams?

Example 33

hard
A multistep synthesis has yields 90%90\%, 80%80\%, and 50%50\% across three steps. If the step-1 theoretical mass is 200 g200\text{ g}, what is the final actual yield?

Example 34

hard
N2+3H22NH3N_2 + 3H_2 \rightarrow 2NH_3. From 2.0 mol2.0\text{ mol} N2N_2 with excess H2H_2, 51 g51\text{ g} of NH3NH_3 (M=17M=17) is collected. Find percent yield.

Example 35

hard
A reaction's theoretical yield is 12.0 g12.0\text{ g}. After purification, 9.6 g9.6\text{ g} of 98%98\%-pure product is recovered. What is the percent yield of pure compound?

Example 36

hard
An industrial process predicts 500 kg500\text{ kg} of product per batch. Two consecutive batches actually produce 410 kg410\text{ kg} and 440 kg440\text{ kg}. What is the average percent yield?

Example 37

hard
A reaction with limiting reagent gives a theoretical yield of 0.080 mol0.080\text{ mol} product. The student weighs 4.0 g4.0\text{ g} of product (M=64 g/molM=64\text{ g/mol}). Find percent yield.

Example 38

challenge
C2H4+H2C2H6C_2H_4 + H_2 \rightarrow C_2H_6. From 14.0 g14.0\text{ g} C2H4C_2H_4 (M=28M=28) and excess H2H_2, the actual yield of ethane (M=30M=30) is 13.5 g13.5\text{ g}. Determine the percent yield to three significant figures.

Background Knowledge

These ideas may be useful before you work through the harder examples.

theoretical yield