Work-Energy Theorem Examples in Physics

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Work-Energy Theorem.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Physics.

Concept Recap

The net work done on an object equals the change in its kinetic energy β€” the bridge between force and motion.

The total work done on an object is exactly what changes its kinetic energy.

Read the full concept explanation β†’

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: This theorem bridges force-based thinking (work) with energy-based thinking (kinetic energy).

Common stuck point: Only net work changes KEβ€”individual forces may do positive or negative work.

Worked Examples

Example 1

easy
A 4 \text{ kg} box initially at rest is pushed with a net force of 20 \text{ N} over 5 \text{ m}. What is the final speed of the box?

Solution

  1. 1
    The work-energy theorem states: W_{\text{net}} = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2.
  2. 2
    Net work done: W = Fd = 20 \times 5 = 100 \text{ J}.
  3. 3
    Since v_i = 0: 100 = \frac{1}{2}(4)v_f^2 \implies v_f = \sqrt{\frac{200}{4}} = \sqrt{50} \approx 7.07 \text{ m/s}

Answer

v_f \approx 7.07 \text{ m/s}
The work-energy theorem directly connects the net work done on an object to its change in kinetic energy. It provides an alternative to using kinematics equations for finding final speeds.

Example 2

medium
A 1500 \text{ kg} car traveling at 25 \text{ m/s} brakes with a friction force of 7500 \text{ N}. How far does it take to stop?

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

medium
A 0.5 \text{ kg} ball moving at 8 \text{ m/s} is hit by a bat that does 25 \text{ J} of work on it. What is the ball's final speed?

Example 2

hard
A 2 \text{ kg} block slides down a rough incline (\mu_k = 0.2) of height 5 \text{ m} and length 10 \text{ m}, starting from rest. What is its speed at the bottom? Use g = 9.8 \text{ m/s}^2.

Related Concepts

Background Knowledge

These ideas may be useful before you work through the harder examples.

workkinetic energy