Resistance Physics Example 2

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Example 2

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A wire has length 2ย m2 \text{ m}, cross-sectional area 1ร—10โˆ’6ย m21 \times 10^{-6} \text{ m}^2, and resistivity ฯ=1.7ร—10โˆ’8ย ฮฉโ‹…m\rho = 1.7 \times 10^{-8} \text{ } \Omega \cdot \text{m} (copper). What is its resistance?

Solution

  1. 1
    Use the resistance formula: R=ฯLAR = \frac{\rho L}{A}.
  2. 2
    Substitute the given values: R=1.7ร—10โˆ’8ร—21ร—10โˆ’6=3.4ร—10โˆ’81ร—10โˆ’6R = \frac{1.7 \times 10^{-8} \times 2}{1 \times 10^{-6}} = \frac{3.4 \times 10^{-8}}{1 \times 10^{-6}}.
  3. 3
    R=0.034ย ฮฉR = 0.034 \text{ } \Omega

Answer

R=0.034ย ฮฉR = 0.034 \text{ } \Omega
Resistance depends on the material (resistivity), length, and cross-sectional area. Longer wires have more resistance; thicker wires have less.

About Resistance

A measure of how strongly a material opposes electric current, measured in ohms (ฮฉ\Omega) โ€” higher resistance means less current for a given voltage.

Learn more about Resistance โ†’

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