Parallel Circuit Physics Example 5

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Example 5

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Two resistors (10 Ω10 \text{ } \Omega and 15 Ω15 \text{ } \Omega) are connected in parallel across a 30 V30 \text{ V} supply. Find: (a) total resistance, (b) total current, (c) current through each resistor.

Solution

  1. 1
    (a) 1RT=110+115=330+230=530\frac{1}{R_T} = \frac{1}{10} + \frac{1}{15} = \frac{3}{30} + \frac{2}{30} = \frac{5}{30}, so RT=6 ΩR_T = 6 \text{ } \Omega.
  2. 2
    (b) Itotal=VRT=306=5 AI_{\text{total}} = \frac{V}{R_T} = \frac{30}{6} = 5 \text{ A}.
  3. 3
    (c) I10=3010=3 AI_{10} = \frac{30}{10} = 3 \text{ A}; I15=3015=2 AI_{15} = \frac{30}{15} = 2 \text{ A}. Check: 3+2=5 A3 + 2 = 5 \text{ A}.

Answer

(a)  6 Ω;(b)  5 A;(c)  3 A and 2 A(a)\; 6 \text{ } \Omega; \quad (b)\; 5 \text{ A}; \quad (c)\; 3 \text{ A and } 2 \text{ A}
In parallel, voltage is the same across all branches, but current splits. More current flows through the smaller resistance. The total resistance is always less than the smallest individual resistor.

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A parallel circuit connects components in separate branches between two common nodes, so each component gets the full source voltage.

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