Ohm's Law Physics Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

medium
What voltage is needed to push 0.25 A0.25 \text{ A} through a 100 Ω100 \text{ } \Omega resistor?

Solution

  1. 1
    Apply Ohm's law: V=IRV = IR.
  2. 2
    V=0.25×100=25 VV = 0.25 \times 100 = 25 \text{ V}

Answer

V=25 VV = 25 \text{ V}
Ohm's law can be rearranged to find voltage, current, or resistance. Here we find the voltage required to drive a specific current through a known resistance.

About Ohm's Law

The fundamental relationship stating that the voltage (VV) across an ohmic conductor equals the current (II) flowing through it multiplied by its resistance (RR).

Learn more about Ohm's Law →

More Ohm's Law Examples

Example 1 easy

A [formula] battery is connected to a [formula] resistor. What current flows?

Example 2 medium

A heater draws [formula] from a [formula] supply. What is its resistance, and how much power does it

Example 4 medium

A resistor in a circuit has a current of [formula] flowing through it when connected to a [formula]

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