Newton's Third Law Physics Example 2

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Example 2

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A 70 kg70 \text{ kg} skater pushes a 50 kg50 \text{ kg} skater with a force of 100 N100 \text{ N}. What is the acceleration of each skater?

Solution

  1. 1
    By Newton's third law, the 50 kg50 \text{ kg} skater pushes back on the 70 kg70 \text{ kg} skater with 100 N100 \text{ N}.
  2. 2
    Acceleration of the 50 kg50 \text{ kg} skater: a1=10050=2 m/s2a_1 = \frac{100}{50} = 2 \text{ m/s}^2
  3. 3
    Acceleration of the 70 kg70 \text{ kg} skater: a2=100701.43 m/s2a_2 = \frac{100}{70} \approx 1.43 \text{ m/s}^2

Answer

a50=2 m/s2,a701.43 m/s2a_{50} = 2 \text{ m/s}^2, \quad a_{70} \approx 1.43 \text{ m/s}^2
The forces are equal and opposite (third law), but the accelerations differ because the skaters have different masses (second law).

About Newton's Third Law

For every action force, there is an equal in magnitude and opposite in direction reaction force.

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