Magnetic Force Physics Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
A proton (q=1.6×10−19 Cq = 1.6 \times 10^{-19} \text{ C}) moves at 5×106 m/s5 \times 10^6 \text{ m/s} perpendicular to a 0.3 T0.3 \text{ T} magnetic field. What is the magnetic force on the proton?

Solution

  1. 1
    Use F=qvBsin⁡θF = qvB\sin\theta with θ=90°\theta = 90°.
  2. 2
    F=1.6×10−19×5×106×0.3×1F = 1.6 \times 10^{-19} \times 5 \times 10^6 \times 0.3 \times 1
  3. 3
    F=2.4×10−13 NF = 2.4 \times 10^{-13} \text{ N}

Answer

F=2.4×10−13 NF = 2.4 \times 10^{-13} \text{ N}
The magnetic force on a moving charged particle is perpendicular to both the velocity and the magnetic field. It causes the particle to move in a circular path rather than speeding it up or slowing it down.

About Magnetic Force

The force exerted on a moving charge or current-carrying conductor by a magnetic field.

Learn more about Magnetic Force →

More Magnetic Force Examples

Example 2 medium

A wire carrying [formula] is [formula] long and placed at [formula] to a [formula] magnetic field. W

Example 3 medium

A proton ([formula]) moves at [formula] perpendicular to a [formula] magnetic field. Find the magnet

Example 4 medium

An electron ([formula], [formula]) moves at [formula] perpendicular to a [formula] field. What is th

Example 5 hard

Two parallel wires [formula] apart each carry [formula] in the same direction. What is the force per

← All Magnetic Force Examples Magnetic Force Concept