Faraday's Law Physics Example 3

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Example 3

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A coil of 5050 turns has an area of 0.01 m20.01 \text{ m}^2. The magnetic field through it decreases from 0.8 T0.8 \text{ T} to 0.2 T0.2 \text{ T} in 0.5 s0.5 \text{ s}. What is the average induced EMF?

Solution

  1. 1
    Change in flux per turn: ΔΦ=(0.20.8)×0.01=0.006 Wb\Delta\Phi = (0.2 - 0.8) \times 0.01 = -0.006 \text{ Wb}.
  2. 2
    Induced EMF: E=NΔΦΔt=50×0.0060.5=0.6 V\mathcal{E} = -N\frac{\Delta\Phi}{\Delta t} = -50 \times \frac{-0.006}{0.5} = 0.6 \text{ V}

Answer

E=0.6 V\mathcal{E} = 0.6 \text{ V}
The induced EMF is proportional to the rate of change of flux and the number of turns. Lenz's law tells us the induced current opposes the change that caused it.

About Faraday's Law

The induced EMF in a circuit equals the negative rate of change of magnetic flux through the circuit.

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