Electromagnetic Induction Physics Example 3

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Example 3

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A bar magnet is pushed into a coil of 100100 turns, increasing the flux through each turn from 00 to 0.004 Wb0.004 \text{ Wb} in 0.2 s0.2 \text{ s}. What is the induced EMF? If the coil has resistance 5 Ω5 \text{ } \Omega, what current flows?

Solution

  1. 1
    Induced EMF: E=NΔΦΔt=100×0.0040.2=100×0.02=2 V\mathcal{E} = N\frac{\Delta\Phi}{\Delta t} = 100 \times \frac{0.004}{0.2} = 100 \times 0.02 = 2 \text{ V}.
  2. 2
    Induced current: I=ER=25=0.4 AI = \frac{\mathcal{E}}{R} = \frac{2}{5} = 0.4 \text{ A}

Answer

E=2 V,I=0.4 A\mathcal{E} = 2 \text{ V}, \quad I = 0.4 \text{ A}
Pushing a magnet into a coil changes the flux and induces an EMF. The induced current creates its own magnetic field that opposes the magnet's motion (Lenz's law), requiring effort to push the magnet in.

About Electromagnetic Induction

The process by which a changing magnetic flux through a conducting loop produces a voltage (electromotive force, EMF) across the conductor, which can drive an.

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