Zeros of a Quadratic Examples in Math

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Zeros of a Quadratic.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

The zeros (or roots) of a quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c are the values of xx where f(x)=0f(x) = 0. Graphically, they are the xx-intercepts of the parabola.

The zeros are where the parabola crosses or touches the xx-axis. A parabola can cross twice (two zeros), just touch once (one repeated zero), or miss entirely (no real zeros). You can find them by factoring, completing the square, or using the quadratic formula.

Read the full concept explanation β†’

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: The zeros are the x-values where a quadratic equals zero β€” its x-intercepts.

Common stuck point: The procedure for zeros of a quadratic is the easy part; the trap is taking only the ++ branch of Β±\pm. Asking "Am I looking for the x-values that make the quadratic equal zero?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Am I looking for the x-values that make the quadratic equal zero?

Worked Examples

Example 1

easy
Find the zeros of f(x)=x2βˆ’7x+10f(x) = x^2 - 7x + 10.

Answer

x=2Β andΒ x=5x = 2 \text{ and } x = 5

First step

1
Set f(x)=0f(x) = 0: x2βˆ’7x+10=0x^2 - 7x + 10 = 0.

Full solution

  1. 2
    Factor: (xβˆ’2)(xβˆ’5)=0(x - 2)(x - 5) = 0.
  2. 3
    Zeros: x=2x = 2 and x=5x = 5.
The zeros of a function are the xx-values where f(x)=0f(x) = 0. They correspond to the xx-intercepts of the graph.

Example 2

medium
Find the zeros of g(x)=2x2βˆ’8xg(x) = 2x^2 - 8x.

Example 3

medium
Find the zeros of f(x)=x2+6x+5f(x) = x^2 + 6x + 5 by factoring.

Example 4

hard
A ball's height (m) is h(t)=βˆ’5t2+20th(t) = -5t^2 + 20t. When does it hit the ground?

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Find the zeros of h(x)=x2βˆ’1h(x) = x^2 - 1.

Example 2

hard
How many zeros does f(x)=x2+4f(x) = x^2 + 4 have over the reals?

Example 3

easy
Find the zeros of f(x)=(xβˆ’4)(x+2)f(x) = (x-4)(x+2).

Example 4

easy
Find the zeros of f(x)=x2βˆ’9f(x) = x^2 - 9.

Example 5

easy
How many real zeros does f(x)=x2+1f(x) = x^2 + 1 have?

Example 6

easy
Find the zeros of f(x)=x2βˆ’5x+6f(x) = x^2 - 5x + 6.

Example 7

easy
Find the zero of f(x)=(xβˆ’7)2f(x) = (x-7)^2.

Example 8

easy
Is f(0)f(0) a zero of f(x)=x2βˆ’4f(x) = x^2 - 4?

Example 9

easy
Find the zeros of f(x)=2x2βˆ’8f(x) = 2x^2 - 8.

Example 10

easy
How many zeros does f(x)=x2βˆ’6x+9f(x) = x^2 - 6x + 9 have?

Example 11

medium
Find the zeros of f(x)=x2βˆ’2xβˆ’8f(x) = x^2 - 2x - 8 by factoring.

Example 12

medium
Find the zeros of f(x)=x2βˆ’4x+1f(x) = x^2 - 4x + 1 using the quadratic formula.

Example 13

medium
Find the zeros of f(x)=2x2+5x+2f(x) = 2x^2 + 5x + 2.

Example 14

medium
Use the discriminant to find how many real zeros f(x)=x2+3x+5f(x)=x^2+3x+5 has.

Example 15

medium
If 33 is a zero of f(x)=x2+bxβˆ’12f(x) = x^2 + bx - 12, find bb.

Example 16

medium
Find the zeros of f(x)=x2+4xf(x) = x^2 + 4x and the yy-intercept.

Example 17

medium
The zeros of a quadratic are βˆ’2-2 and 66. Find the axis of symmetry.

Example 18

medium
Find the zeros of f(x)=x2+7x+10f(x) = x^2 + 7x + 10.

Example 19

medium
If βˆ’4-4 is a zero of f(x)=x2+bx+4f(x) = x^2 + bx + 4, find bb.

Example 20

challenge
A quadratic f(x)=x2+bx+cf(x)=x^2+bx+c has zeros 22 and βˆ’5-5. Find bb and cc.

Example 21

challenge
Find the zeros of f(x)=x2βˆ’6x+7f(x) = x^2 - 6x + 7 and simplify the radical.

Example 22

challenge
For what cc does f(x)=x2βˆ’8x+cf(x) = x^2 - 8x + c have a repeated zero, and what is it?

Example 23

easy
Find the zeros of f(x)=(xβˆ’3)(x+8)f(x) = (x - 3)(x + 8).

Example 24

easy
Find the zeros of f(x)=x2βˆ’16f(x) = x^2 - 16.

Example 25

easy
Find the zeros of f(x)=x2+xβˆ’6f(x) = x^2 + x - 6.

Example 26

easy
Find the zeros of f(x)=3x2βˆ’12xf(x) = 3x^2 - 12x.

Example 27

easy
Find the zeros of f(x)=x2βˆ’100f(x) = x^2 - 100.

Example 28

medium
Find the zeros of f(x)=x2βˆ’10x+25f(x) = x^2 - 10x + 25.

Example 29

medium
Use the quadratic formula to find the zeros of f(x)=x2+2xβˆ’4f(x) = x^2 + 2x - 4.

Example 30

medium
Find the zeros of f(x)=3x2βˆ’7x+2f(x) = 3x^2 - 7x + 2.

Example 31

medium
If 55 is a zero of f(x)=x2βˆ’8x+cf(x) = x^2 - 8x + c, find cc.

Example 32

medium
The zeros of a quadratic are βˆ’3-3 and 77. Find the axis of symmetry.

Example 33

medium
Find the sum and product of the zeros of f(x)=2x2+5xβˆ’3f(x) = 2x^2 + 5x - 3.

Example 34

medium
Find the zeros of f(x)=x2βˆ’6x+9f(x) = x^2 - 6x + 9.

Example 35

medium
Find the zeros of f(x)=βˆ’x2+5x+6f(x) = -x^2 + 5x + 6.

Example 36

hard
Find the zeros of f(x)=x2βˆ’10x+18f(x) = x^2 - 10x + 18 (use the quadratic formula and simplify).

Example 37

hard
If a quadratic with leading coefficient 11 has zeros βˆ’1-1 and 44, write it in standard form.

Example 38

hard
For what value(s) of kk does f(x)=x2+kx+9f(x) = x^2 + kx + 9 have a repeated zero?

Example 39

hard
For what value(s) of kk does f(x)=x2+kx+4f(x) = x^2 + kx + 4 have no real zeros?

Example 40

hard
Find the zeros of f(x)=4x2βˆ’4xβˆ’3f(x) = 4x^2 - 4x - 3.

Example 41

hard
Find the zeros of f(x)=x2+4x+1f(x) = x^2 + 4x + 1 by completing the square.

Example 42

challenge
A quadratic f(x)=ax2+bx+cf(x) = ax^2 + bx + c has zeros rr and ss with r+s=8r + s = 8 and rs=12rs = 12. Find b/ab/a and c/ac/a.

Example 43

challenge
If f(x)=x2+px+qf(x) = x^2 + px + q has zeros rr and ss with r+s=5r + s = 5 and r2+s2=13r^2 + s^2 = 13, find pp and qq.

Background Knowledge

These ideas may be useful before you work through the harder examples.

quadratic functionsfactoringquadratic formula