Vertex and Axis of Symmetry Math Example 1

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Example 1

easy
Find the vertex and axis of symmetry of f(x)=x2+8x+12f(x) = x^2 + 8x + 12.

Solution

  1. 1
    Axis of symmetry: x=โˆ’b2a=โˆ’82=โˆ’4x = -\frac{b}{2a} = -\frac{8}{2} = -4.
  2. 2
    Vertex yy-value: f(โˆ’4)=16โˆ’32+12=โˆ’4f(-4) = 16 - 32 + 12 = -4.
  3. 3
    Vertex: (โˆ’4,โˆ’4)(-4, -4); axis of symmetry: x=โˆ’4x = -4.

Answer

Vertex (โˆ’4,โˆ’4)(-4, -4); axis x=โˆ’4x = -4.
The axis of symmetry is the vertical line x=โˆ’b2ax = -\frac{b}{2a} that passes through the vertex and divides the parabola into two mirror-image halves.

About Vertex and Axis of Symmetry

The vertex of a parabola is the point where it reaches its maximum or minimum value. The axis of symmetry is the vertical line that passes through the vertex, dividing the parabola into two mirror-image halves.

Learn more about Vertex and Axis of Symmetry โ†’

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