Double-Angle Identities Examples: 47 Problems with Answers

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Double-Angle Identities.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Formulas expressing sin⁡(2θ), cos⁡(2θ), and tan⁡(2θ) in terms of single-angle trig functions.

What if both angles in the sum formula are the same? Setting A=B=θ in the sum identities gives you the double-angle formulas. They answer: if you know the trig values for an angle, what are the trig values for twice that angle? The cosine double-angle formula is especially versatile because it has three equivalent forms, each useful in different situations—pick whichever one simplifies your problem.

Read the full concept explanation →

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: sin⁡2θ, cos⁡2θ, tan⁡2θ written from single-angle values, with cosine offering three interchangeable forms.

Common stuck point: The procedure for double-angle identities is the easy part; the trap is writing sin⁡2θ=2sin⁡θ. Asking "Is the angle exactly twice another, so I can express it from single-angle trig values?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Is the angle exactly twice another, so I can express it from single-angle trig values?

Worked Examples

Example 1

easy
If cos⁡(θ)=35, find cos⁡(2θ) using the double-angle formula.

Answer

cos⁡(2θ)=−725

First step

1
Use the double-angle formula: cos⁡(2θ)=2cos⁡2(θ)−1.

Full solution

  1. 2
    Substitute: cos⁡(2θ)=2(35)2−1=2⋅925−1.
  2. 3
    =1825−1=1825−2525=−725.
The double-angle formula for cosine has three equivalent forms: cos⁡(2θ)=cos⁡2θ−sin⁡2θ=2cos⁡2θ−1=1−2sin⁡2θ. Choose the form that uses the information you have — here we used 2cos⁡2θ−1 since we knew cosine.

Example 2

medium
Find sin⁡(2θ) given that tan⁡(θ)=512 and θ is in Quadrant I.

Example 3

medium
Solve cos⁡(2x)=cos⁡x on [0,2π).

Example 4

medium
Use power-reduction to write cos⁡2x in terms of cos⁡(2x).

Example 5

hard
Prove that sin⁡(2θ)1+cos⁡(2θ)=tan⁡θ.

Example 6

hard
Show that sin⁡(3θ)=3sin⁡θ−4sin⁡3θ using sin⁡(3θ)=sin⁡(2θ+θ).

Example 7

challenge
Find the maximum value of f(θ)=sin⁡θcos⁡θ+cos⁡(2θ) on [0,2π).

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

medium
Simplify cos⁡2(x)−sin⁡2(x) using a double-angle identity.

Example 2

hard
Solve sin⁡(2x)=cos⁡(x) for x∈[0,2π).

Example 3

easy
State the double-angle formula for sin⁡(2θ).

Example 4

easy
State one form of the double-angle formula for cos⁡(2θ).

Example 5

easy
Give the form of cos⁡(2θ) in terms of cos⁡2θ only.

Example 6

easy
Give the form of cos⁡(2θ) in terms of sin⁡2θ only.

Example 7

easy
If sin⁡θ=35 and cos⁡θ=45, find sin⁡(2θ).

Example 8

easy
State the double-angle formula for tan⁡(2θ).

Example 9

easy
If cos⁡θ=35, use a double-angle form to find cos⁡(2θ).

Example 10

easy
Is sin⁡(2θ)=2sin⁡θ correct? Answer yes or no.

Example 11

medium
If sin⁡θ=513 and θ is in Quadrant I, find cos⁡(2θ).

Example 12

medium
If cos⁡θ=−35 and θ is in Quadrant II, find sin⁡(2θ).

Example 13

medium
Simplify 2sin⁡15°cos⁡15°.

Example 14

medium
Simplify cos⁡225°−sin⁡225°.

Example 15

medium
Simplify 1−2sin⁡230°.

Example 16

medium
If tan⁡θ=13, find tan⁡(2θ).

Example 17

medium
Express sin⁡(4θ) using a double-angle formula once.

Example 18

medium
If sin⁡θ=45 and θ is in Quadrant I, find cos⁡(2θ).

Example 19

medium
Simplify 2tan⁡22.5°1−tan⁡222.5°.

Example 20

challenge
If cos⁡θ=45 and θ is in Quadrant IV, find sin⁡(2θ) and cos⁡(2θ).

Example 21

challenge
Prove the power-reduction formula sin⁡2θ=1−cos⁡(2θ)2.

Example 22

challenge
If sin⁡(2θ)=12, find the value of sin⁡θcos⁡θ.

Example 23

easy
Compute 2sin⁡45°cos⁡45°.

Example 24

easy
If sin⁡θ=12 and cos⁡θ=32, find sin⁡(2θ).

Example 25

easy
Simplify 2cos⁡260°−1.

Example 26

easy
Find tan⁡(2⋅0°) and use the formula to verify it equals 0.

Example 27

easy
Simplify 1−2sin⁡245°.

Example 28

medium
If sin⁡θ=−35 and θ is in Quadrant III, find sin⁡(2θ).

Example 29

medium
If cos⁡θ=725 and θ is in Quadrant IV, find cos⁡(2θ).

Example 30

medium
Simplify sin⁡(2θ)sin⁡θ.

Example 31

medium
Write cos⁡4θ in terms of cos⁡2θ using a double-angle formula.

Example 32

medium
If tan⁡θ=−12, find tan⁡(2θ).

Example 33

medium
Express sin⁡θcos⁡θ in terms of sin⁡(2θ).

Example 34

medium
Simplify 1−cos⁡(2x)sin⁡(2x).

Example 35

medium
If cos⁡θ=1213 and θ is in Quadrant I, find tan⁡(2θ).

Example 36

hard
Solve sin⁡(2x)+sin⁡x=0 on [0,2π).

Example 37

hard
If sin⁡θ+cos⁡θ=12, find sin⁡(2θ).

Example 38

hard
Solve cos⁡(2x)=sin⁡x on [0,2π).

Example 39

hard
Find the exact value of sin⁡22.5° using a half-angle approach derived from the cosine double-angle identity.

Example 40

challenge
If sin⁡(2θ)=35 and θ∈(0,π/4), find sin⁡θ−cos⁡θ.

Background Knowledge

These ideas may be useful before you work through the harder examples.

trig identities sum difference