Triangle Angle Sum Math Example 4

Follow the full solution, then compare it with the other examples linked below.

Example 4

hard
In ABC\triangle ABC, A=2x+10°\angle A = 2x + 10°, B=3x5°\angle B = 3x - 5°, C=x+15°\angle C = x + 15°. Find all three angles.

Solution

  1. 1
    Step 1: Apply the angle sum: (2x+10)+(3x5)+(x+15)=180(2x+10) + (3x-5) + (x+15) = 180.
  2. 2
    Step 2: Combine like terms: 6x+20=1806x + 20 = 180, so 6x=1606x = 160, giving x=1606=26.6°x = \frac{160}{6} = 26.\overline{6}°.
  3. 3
    Step 3: Compute each angle: A=2(26.6)+10=63.3°\angle A = 2(26.\overline{6})+10 = 63.\overline{3}°; B=3(26.6)5=75°\angle B = 3(26.\overline{6})-5 = 75°; C=26.6+15=41.6°\angle C = 26.\overline{6}+15 = 41.\overline{6}°.
  4. 4
    Step 4: Check: 63.3+75+41.6=180°63.\overline{3} + 75 + 41.\overline{6} = 180°. ✓

Answer

A63.3°\angle A \approx 63.3°, B=75°\angle B = 75°, C41.7°\angle C \approx 41.7°.
Setting up an equation using the angle sum property and solving for the variable is the standard approach to algebraic angle problems. After finding xx, substitute back to get each angle and verify the sum equals 180°.

About Triangle Angle Sum

The three interior angles of any triangle always sum to exactly 180°180°, so knowing two angles determines the third.

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