Transfer of Ideas Math Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
The idea of completing the square to solve x2+6x+5=0x^2+6x+5=0 transfers to converting x2+6x+5x^2+6x+5 to vertex form. Show both applications.

Solution

  1. 1
    Solving: x2+6x+5=0β‡’(x+3)2βˆ’9+5=0β‡’(x+3)2=4β‡’x=βˆ’3Β±2=βˆ’1x^2+6x+5=0 \Rightarrow (x+3)^2-9+5=0 \Rightarrow (x+3)^2=4 \Rightarrow x=-3\pm 2 = -1 or βˆ’5-5.
  2. 2
    Vertex form: f(x)=x2+6x+5=(x+3)2βˆ’4f(x) = x^2+6x+5 = (x+3)^2-4. Vertex at (βˆ’3,βˆ’4)(-3,-4).
  3. 3
    The same algebraic manipulation (completing the square) solves the equation and reveals the geometric structure of the parabola.

Answer

x=βˆ’1Β orΒ x=βˆ’5;f(x)=(x+3)2βˆ’4Β (vertexΒ atΒ (βˆ’3,βˆ’4))x=-1 \text{ or } x=-5;\quad f(x)=(x+3)^2-4 \text{ (vertex at }(-3,-4))
Transfer of ideas means recognising that a technique learned in one context (solving equations) applies in another context (graphing parabolas). The shared technique is completing the square.

About Transfer of Ideas

The ability to recognize that a technique or concept from one area of mathematics applies, possibly in adapted form, to a different area.

Learn more about Transfer of Ideas β†’

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