Step Function Intuition Math Example 4

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Example 4

hard
Define f(x)=โŒŠ2xโŒ‹f(x) = \lfloor 2x \rfloor. Find all xx in [0,2][0, 2] where f(x)=3f(x) = 3, and sketch ff on [0,2][0,2].

Solution

  1. 1
    Solve โŒŠ2xโŒ‹=3\lfloor 2x \rfloor = 3: this requires 3โ‰ค2x<4โ‡’32โ‰คx<23 \leq 2x < 4 \Rightarrow \frac{3}{2} \leq x < 2.
  2. 2
    So f(x)=3f(x)=3 on [32,2)[\frac{3}{2}, 2). Sketch: steps at heights 0,1,2,30,1,2,3 over [0,2][0,2], each step of width 12\frac{1}{2}: [0,12),[12,1),[1,32),[32,2)[0,\frac{1}{2}), [\frac{1}{2},1), [1,\frac{3}{2}), [\frac{3}{2},2).

Answer

f(x)=3f(x) = 3 for xโˆˆ[32,2)x \in \left[\dfrac{3}{2}, 2\right)
Scaling the argument of a floor function by 22 doubles the frequency of the steps (halves the step width). Each step now has length 12\frac{1}{2} instead of 11.

About Step Function Intuition

A step function is piecewise constant โ€” it takes a fixed value on each of several intervals, jumping abruptly at the interval boundaries.

Learn more about Step Function Intuition โ†’

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