Stability Math Example 4

Follow the full solution, then compare it with the other examples linked below.

Example 4

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For the map h(x)=12x+4h(x) = \frac{1}{2}x + 4, find the fixed point and verify stability by iterating from x0=0x_0 = 0 and x0=20x_0 = 20 for three steps each.

Solution

  1. 1
    Fixed point: xโˆ—=12xโˆ—+4โ‡’12xโˆ—=4โ‡’xโˆ—=8x^* = \frac{1}{2}x^*+4 \Rightarrow \frac{1}{2}x^*=4 \Rightarrow x^*=8. โˆฃhโ€ฒ(x)โˆฃ=โˆฃ12โˆฃ=0.5<1|h'(x)|=|\frac{1}{2}|=0.5<1: stable.
  2. 2
    From x0=0x_0=0: x1=4,x2=6,x3=7x_1=4, x_2=6, x_3=7. From x0=20x_0=20: x1=14,x2=11,x3=9.5x_1=14, x_2=11, x_3=9.5. Both sequences approach 88.

Answer

Fixed point xโˆ—=8x^*=8 (stable); both orbits converge toward 88
A stable fixed point acts as an attractor. Regardless of starting point, iteration of a contraction map converges to the unique fixed point. The convergence rate is governed by โˆฃfโ€ฒ(xโˆ—)โˆฃ=0.5|f'(x^*)|=0.5 per step.

About Stability

A system is stable at an equilibrium if small perturbations cause it to return toward that equilibrium; unstable if small perturbations cause it to move away.

Learn more about Stability โ†’

More Stability Examples