Specialization Examples in Math

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Specialization.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Applying a general theorem or formula to a specific case by substituting particular values for the variables or parameters.

What does this general statement say about MY specific situation?

Read the full concept explanation โ†’

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Specialization applies a general theorem or formula to a concrete situation by substituting particular values for its variables.

Common stuck point: The procedure for specialization is the easy part; the trap is substituting values into the wrong general formula. Asking "Am I taking a general formula or theorem and feeding it specific values for a single concrete case?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Am I taking a general formula or theorem and feeding it specific values for a single concrete case?

Worked Examples

Example 1

easy
The Binomial Theorem states (a+b)n=โˆ‘k=0n(nk)anโˆ’kbk(a+b)^n = \sum_{k=0}^{n}\binom{n}{k}a^{n-k}b^k. Specialise to a=1,b=1a=1, b=1 and a=1,b=โˆ’1a=1, b=-1 to obtain two identities.

Answer

โˆ‘k=0n(nk)=2n,โˆ‘k=0n(nk)(โˆ’1)k=0\sum_{k=0}^{n}\binom{n}{k}=2^n,\quad \sum_{k=0}^{n}\binom{n}{k}(-1)^k=0

First step

1
The Binomial Theorem gives (a+b)n=โˆ‘k=0n(nk)anโˆ’kbk(a+b)^n = \sum_{k=0}^{n}\binom{n}{k}a^{n-k}b^k. Specialization means substituting specific values for the parameters to obtain concrete identities.

Full solution

  1. 2
    Substitute a=1,b=1a=1, b=1: (1+1)n=โˆ‘k=0n(nk)1nโˆ’kโ‹…1k=โˆ‘k=0n(nk)(1+1)^n = \sum_{k=0}^{n}\binom{n}{k}1^{n-k}\cdot 1^k = \sum_{k=0}^{n}\binom{n}{k}. Since the left side equals 2n2^n, we get the identity โˆ‘k=0n(nk)=2n\sum_{k=0}^{n}\binom{n}{k} = 2^n.
  2. 3
    Substitute a=1,b=โˆ’1a=1, b=-1: (1โˆ’1)n=โˆ‘k=0n(nk)(โˆ’1)k(1-1)^n = \sum_{k=0}^{n}\binom{n}{k}(-1)^k. For nโ‰ฅ1n \ge 1 the left side is 0n=00^n = 0, giving the alternating-sum identity โˆ‘k=0n(nk)(โˆ’1)k=0\sum_{k=0}^{n}\binom{n}{k}(-1)^k = 0.
Specialisation plugs specific values into a general formula to obtain particular results. The Binomial Theorem is a powerful source of combinatorial identities via specialisation.

Example 2

medium
The AM-GM inequality states: for positive reals a,ba,b, a+b2โ‰ฅab\frac{a+b}{2} \ge \sqrt{ab}. Specialise to a=x2a = x^2 and b=1x2b = \frac{1}{x^2} (for xโ‰ 0x \ne 0) and state what you get.

Example 3

medium
The Pythagorean identity is sinโก2ฮธ+cosโก2ฮธ=1\sin^2\theta+\cos^2\theta=1. Specialize at ฮธ=60โˆ˜\theta=60^\circ to verify it.

Example 4

medium
Specialize Heron's formula A=s(sโˆ’a)(sโˆ’b)(sโˆ’c)A=\sqrt{s(s-a)(s-b)(s-c)} (with s=a+b+c2s=\tfrac{a+b+c}{2}) to a 33-44-55 triangle. Confirm the area.

Example 5

hard
De Moivre: (cosโกฮธ+isinโกฮธ)n=cosโก(nฮธ)+isinโก(nฮธ)(\cos\theta+i\sin\theta)^n=\cos(n\theta)+i\sin(n\theta). Specialize to ฮธ=60โˆ˜,n=3\theta=60^\circ, n=3 and identify the result.

Example 6

medium
Specialize the dot product formula uโ‹…v=u1v1+u2v2+u3v3\mathbf u\cdot\mathbf v=u_1v_1+u_2v_2+u_3v_3 to u=(1,2,3),v=(4,โˆ’1,2)\mathbf u=(1,2,3), \mathbf v=(4,-1,2).

Example 7

challenge
The general formula 1ab=1bโˆ’a(1aโˆ’1b)\dfrac{1}{ab}=\dfrac{1}{b-a}\left(\dfrac{1}{a}-\dfrac{1}{b}\right) holds for aโ‰ ba\ne b. Specialize to a=k,b=k+1a=k, b=k+1 and use it to telescope โˆ‘k=1n1k(k+1)\sum_{k=1}^{n}\dfrac{1}{k(k+1)}.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
The general formula for the sum of a geometric series is Sn=a(rnโˆ’1)rโˆ’1S_n = \frac{a(r^n-1)}{r-1}. Specialise to a=1,r=2a=1, r=2 and compute S5S_5.

Example 2

medium
The general derivative rule is (xn)โ€ฒ=nxnโˆ’1(x^n)' = nx^{n-1}. Specialise to find the derivatives of x3x^3, x1/2x^{1/2}, and xโˆ’1x^{-1}.

Example 3

easy
The area of a rectangle is A=lwA = lw. Specialize to a square of side ss.

Example 4

easy
Use (a+b)2=a2+2ab+b2(a+b)^2=a^2+2ab+b^2 to expand (x+1)2(x+1)^2.

Example 5

easy
The general line is y=mx+by=mx+b. Specialize to slope 22 and intercept โˆ’3-3.

Example 6

easy
Specialize ana^n to find a0a^0 for aโ‰ 0a \ne 0.

Example 7

easy
The quadratic formula gives roots of ax2+bx+c=0ax^2+bx+c=0. Specialize to x2โˆ’5x+6=0x^2-5x+6=0.

Example 8

easy
Specialize the circle area A=ฯ€r2A=\pi r^2 to radius 33.

Example 9

easy
The sum 1+2+โ‹ฏ+n=n(n+1)21+2+\dots+n=\frac{n(n+1)}{2}. Specialize to n=10n=10.

Example 10

easy
Specialize the distributive law a(b+c)=ab+aca(b+c)=ab+ac to expand 5(x+2)5(x+2).

Example 11

medium
Specialize the law of cosines c2=a2+b2โˆ’2abcosโกCc^2=a^2+b^2-2ab\cos C to C=90โˆ˜C=90^\circ. What do you recover?

Example 12

medium
Specialize (nk)=n!k!(nโˆ’k)!\binom{n}{k}=\frac{n!}{k!(n-k)!} to compute (52)\binom{5}{2}.

Example 13

medium
Specialize the geometric series sum a(1โˆ’rn)1โˆ’r\frac{a(1-r^n)}{1-r} to a=1,r=12,n=3a=1,r=\frac12,n=3.

Example 14

medium
Specialize f(x)=ax2+bx+cf(x)=ax^2+bx+c to find its value at x=0x=0. What does this reveal about cc?

Example 15

medium
Specialize the AM-GM inequality a+b2โ‰ฅab\frac{a+b}{2}\ge\sqrt{ab} to a=ba=b. What happens?

Example 16

medium
Specialize the dot product formula uโƒ—โ‹…vโƒ—=โˆฃuโƒ—โˆฃโˆฃvโƒ—โˆฃcosโกฮธ\vec{u}\cdot\vec{v}=|\vec{u}||\vec{v}|\cos\theta to perpendicular vectors. What is the result?

Example 17

challenge
Specialize the binomial theorem (a+b)n=โˆ‘k=0n(nk)anโˆ’kbk(a+b)^n=\sum_{k=0}^{n}\binom{n}{k}a^{n-k}b^k to a=b=1a=b=1. What identity emerges?

Example 18

challenge
Specialize the derivative power rule and chain rule to differentiate f(x)=(3x)2f(x)=(3x)^2 two ways; confirm they agree.

Example 19

challenge
The general solution of dydx=ky\frac{dy}{dx}=ky is y=Cekxy=Ce^{kx}. Specialize to k=1k=1, C=2C=2, and evaluate at x=0x=0.

Example 20

medium
Specialize the cosine double-angle formula cosโก2ฮธ=1โˆ’2sinโก2ฮธ\cos2\theta=1-2\sin^2\theta to ฮธ=30โˆ˜\theta=30^\circ.

Example 21

medium
Specialize the slope formula m=y2โˆ’y1x2โˆ’x1m=\frac{y_2-y_1}{x_2-x_1} to the points (1,2)(1,2) and (4,8)(4,8).

Example 22

medium
Specialize the compound-interest formula A=P(1+r)tA=P(1+r)^t to P=100,r=0.1,t=2P=100, r=0.1, t=2.

Example 23

easy
Specialize the identity a2โˆ’b2=(aโˆ’b)(a+b)a^2 - b^2 = (a-b)(a+b) with a=7,b=3a=7, b=3 to compute 72โˆ’327^2 - 3^2.

Example 24

easy
Specialize the volume formula V=ฯ€r2hV=\pi r^2 h for a cylinder with r=2r=2 and h=5h=5.

Example 25

easy
Specialize the linear function f(x)=mx+bf(x)=mx+b to m=โˆ’1,b=4m=-1, b=4. Compute f(3)f(3).

Example 26

easy
Specialize the sine sum identity sinโก(A+B)=sinโกAcosโกB+cosโกAsinโกB\sin(A+B)=\sin A\cos B+\cos A\sin B to A=B=45โˆ˜A=B=45^\circ and simplify.

Example 27

medium
Specialize the binomial theorem (a+b)n=โˆ‘(nk)anโˆ’kbk(a+b)^n=\sum\binom{n}{k}a^{n-k}b^k to n=3n=3, a=x,b=2a=x, b=2. Write the expanded form.

Example 28

medium
Specialize the matrix-vector product AvA\mathbf v with A=(1234)A=\begin{pmatrix}1&2\\3&4\end{pmatrix} and v=(11)\mathbf v=\begin{pmatrix}1\\1\end{pmatrix}.

Example 29

medium
Specialize the integral โˆซxnโ€‰dx=xn+1n+1+C\int x^n\,dx=\dfrac{x^{n+1}}{n+1}+C (for nโ‰ โˆ’1n\ne -1) to n=4n=4.

Example 30

medium
Specialize the recurrence an+1=2an+1a_{n+1}=2a_n+1 to a0=0a_0=0 and list a1,a2,a3a_1, a_2, a_3.

Example 31

hard
Specialize the Taylor series ex=โˆ‘n=0โˆžxnn!e^x=\sum_{n=0}^\infty \dfrac{x^n}{n!} to x=1x=1, then to the first four terms. Report the partial sum.

Example 32

hard
The Cauchy-Schwarz inequality says (a1b1+a2b2)2โ‰ค(a12+a22)(b12+b22)(a_1b_1+a_2b_2)^2\le (a_1^2+a_2^2)(b_1^2+b_2^2). Specialize to a1=a2=1,b1=x,b2=ya_1=a_2=1, b_1=x, b_2=y and state the resulting inequality.

Example 33

hard
Specialize the law of sines asinโกA=bsinโกB\dfrac{a}{\sin A}=\dfrac{b}{\sin B} to A=30โˆ˜,B=45โˆ˜,a=10A=30^\circ, B=45^\circ, a=10. Find bb.

Example 34

medium
Specialize the identity logโก(xy)=logโกx+logโกy\log(xy)=\log x+\log y to x=8,y=125x=8, y=125 (base 10).

Example 35

hard
Specialize the quadratic formula to a=2,b=4,c=โˆ’30a=2, b=4, c=-30 and find the roots.

Example 36

challenge
Vandermonde's identity: โˆ‘k=0r(mk)(nrโˆ’k)=(m+nr)\sum_{k=0}^{r}\binom{m}{k}\binom{n}{r-k}=\binom{m+n}{r}. Specialize to m=n=rm=n=r and state the result.

Related Concepts

Background Knowledge

These ideas may be useful before you work through the harder examples.

generalization