Sensitivity (Meta) Math Example 3

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Example 3

easy
For f(x)=xf(x)=\sqrt{x}, compute f(100)f(100) and f(104)f(104). By what percentage does ff change when xx increases by 4%?

Solution

  1. 1
    f(100)=10f(100) = 10, f(104)=10410.198f(104) = \sqrt{104} \approx 10.198.
  2. 2
    Change in ff: 0.1980.198. Relative change: 0.19810=1.98%\frac{0.198}{10} = 1.98\%.
  3. 3
    Change in xx: 4%4\%. So a 4% increase in xx causes only about 2% increase in ff.

Answer

4% increase in x2% increase in f  (low sensitivity)\text{4\% increase in }x \Rightarrow \approx 2\%\text{ increase in }f\;(\text{low sensitivity})
The square root function compresses changes: a 4% input change gives only a 2% output change. This follows from the derivative: f(x)/f(x)=12x1/2/x1/2=1/(2x)f'(x)/f(x) = \frac{1}{2x^{1/2}}/x^{1/2} = 1/(2x), giving half the relative change.

About Sensitivity (Meta)

The degree to which a result or output changes in response to small changes in its inputs, parameters, or assumptions.

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