Saturation Examples in Math
Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Saturation.
This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.
Concept Recap
Saturation is the phenomenon where a growing quantity approaches a limiting value asymptotically, with the rate of growth decreasing as the limit is approached.
Room fills until no more people fit. Growth can't continue forever.
Read the full concept explanation โHow to Use These Examples
- Read the first worked example with the solution open so the structure is clear.
- Try the practice problems before revealing each solution.
- Use the related concepts and background knowledge badges if you feel stuck.
What to Focus On
Core idea: Saturation creates an asymptoteโa ceiling the function approaches.
Common stuck point: Saturation isn't stoppingโit's approaching a limit infinitely slowly.
Sense of Study hint: Draw a horizontal dashed line at the limiting value. Then sketch the curve approaching but never quite reaching it.
Worked Examples
Example 1
mediumSolution
- 1 P(0) = \frac{1000}{1+e^{-0.5(0-6)}} = \frac{1000}{1+e^{3}} = \frac{1000}{1+20.09} \approx \frac{1000}{21.09} \approx 47.4.
- 2 P(6) = \frac{1000}{1+e^{0}} = \frac{1000}{1+1} = 500. At t=6, population is at half the maximum.
- 3 \lim_{t\to\infty}P(t): as t\to\infty, e^{-0.5(t-6)}\to0, so P\to\frac{1000}{1+0}=1000. The carrying capacity (saturation level) is L=1000.
Answer
Example 2
hardPractice Problems
Try these problems on your own first, then open the solution to compare your method.
Example 1
easyExample 2
mediumRelated Concepts
Background Knowledge
These ideas may be useful before you work through the harder examples.