Right Triangle Trigonometry Math Example 3

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Example 3

easy
In a right triangle with angle θ=45°\theta = 45° and hypotenuse =8= 8, find both legs.

Solution

  1. 1
    Step 1: Use sin45°=opp8\sin 45° = \frac{\text{opp}}{8}. Since sin45°=22\sin 45° = \frac{\sqrt{2}}{2}, the opposite leg =822=42= 8 \cdot \frac{\sqrt{2}}{2} = 4\sqrt{2}.
  2. 2
    Step 2: By symmetry (45-45-90 triangle), both legs are equal, so the adjacent leg also =425.66= 4\sqrt{2} \approx 5.66.

Answer

Both legs =425.66= 4\sqrt{2} \approx 5.66.
In a 45-45-90 right triangle, both acute angles are equal (45°), so the two legs must be equal. Using sin45°=22\sin 45° = \frac{\sqrt{2}}{2} and the given hypotenuse gives each leg as 22×8=42\frac{\sqrt{2}}{2} \times 8 = 4\sqrt{2}.

About Right Triangle Trigonometry

The three primary trigonometric ratios—sine, cosine, and tangent—defined as ratios of specific sides in a right triangle.

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