Reflection Math Example 4

Follow the full solution, then compare it with the other examples linked below.

Example 4

hard
Reflect the point R(4,1)R(4, 1) over the line y=2y = 2. Find the image coordinates and explain your method.

Solution

  1. 1
    Step 1: The line y=2y = 2 is a horizontal mirror. To reflect over y=cy = c, the rule is (x,y)โ†’(x,2cโˆ’y)(x, y) \to (x, 2c - y).
  2. 2
    Step 2: With c=2c = 2: (x,y)โ†’(x,4โˆ’y)(x, y) \to (x, 4 - y).
  3. 3
    Step 3: R(4,1)โ†’(4,ย 4โˆ’1)=(4,3)R(4, 1) \to (4,\ 4-1) = (4, 3).
  4. 4
    Step 4: Verify: midpoint of (4,1)(4,1) and (4,3)(4,3) is (4,2)(4, 2) which lies on y=2y=2. โœ“

Answer

Rโ€ฒ=(4,3)R' = (4, 3)
Reflecting over a horizontal line y=cy=c keeps the x-coordinate fixed and maps yy to 2cโˆ’y2c - y. This works because the perpendicular distance from the point to the line is โˆฃyโˆ’cโˆฃ|y - c|, and the image is the same distance on the other side: c+(cโˆ’y)=2cโˆ’yc + (c - y) = 2c - y.

About Reflection

A rigid transformation that flips a figure over a line (the mirror line), producing a mirror image.

Learn more about Reflection โ†’

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