Recomposition Examples in Math

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Recomposition.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Recomposition is the process of combining simpler parts, sub-results, or solved sub-problems back together to form a complete solution or to understand the whole structure from its pieces.

After decomposing a problem, you must reassemble the pieces correctly β€” like completing a jigsaw puzzle, the boundary conditions between parts must match.

Read the full concept explanation β†’

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Recomposition reassembles solved subproblems into the whole answer, making sure the seams between parts match.

Common stuck point: The procedure for recomposition is the easy part; the trap is assuming recomposition is just adding. Asking "Have I already solved the pieces, and is my job now to fit them into one whole with matching seams?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Have I already solved the pieces, and is my job now to fit them into one whole with matching seams?

Worked Examples

Example 1

easy
After decomposing x2+5x+6=(x+2)(x+3)x^2 + 5x + 6 = (x+2)(x+3), recompose to solve x2+5x+6=0x^2+5x+6 = 0.

Answer

x=βˆ’2Β orΒ x=βˆ’3x = -2 \text{ or } x = -3

First step

1
Decomposition gave: x2+5x+6=(x+2)(x+3)x^2+5x+6 = (x+2)(x+3).

Full solution

  1. 2
    Set the product equal to zero: (x+2)(x+3)=0(x+2)(x+3) = 0.
  2. 3
    Recompose the solution: either x+2=0x+2=0 (giving x=βˆ’2x=-2) or x+3=0x+3=0 (giving x=βˆ’3x=-3).
  3. 4
    Final answer: x∈{βˆ’2,βˆ’3}x \in \{-2, -3\}.
Recomposition uses the pieces obtained in decomposition to assemble the final answer. The zero-product property lets us read off solutions directly from the factored form.

Example 2

medium
Partial fractions gave 5x+1(x+1)(xβˆ’2)=43(x+1)+113(xβˆ’2)\frac{5x+1}{(x+1)(x-2)} = \frac{4}{3(x+1)}+\frac{11}{3(x-2)}. Recompose to verify by adding the fractions.

Example 3

medium
A trapezoid is decomposed into two triangles via a diagonal. The triangles have area 1515 and 99. Recompose the trapezoid's area.

Example 4

medium
βˆ‘k=14k=10\sum_{k=1}^{4} k = 10 and βˆ‘k=14k2=30\sum_{k=1}^{4} k^2 = 30. Recombine for βˆ‘k=14k(k+1)\sum_{k=1}^{4} k(k+1).

Example 5

medium
Found legs a=7a = 7 and b=24b = 24 of a right triangle. Recompose for the hypotenuse.

Example 6

hard
Complex number z=3+4iz = 3 + 4i was split into real and imaginary parts. Recombine to find zzˉz\bar z.

Example 7

hard
Modular pieces n≑1(mod4)n \equiv 1 \pmod 4, n≑2(mod3)n \equiv 2 \pmod 3. Recombine via CRT for the smallest positive nn.

Example 8

challenge
A combinatorial count is split: pick a chair (55 ways) then assign people (3!=63! = 6 ways). Recombine for the total arrangements.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
You find x=3x=3 and y=1y=1 from solving a system. Recompose by substituting back into both equations to verify.

Example 2

medium
Given the identity sin⁑2ΞΈ=1βˆ’cos⁑2ΞΈ2\sin^2\theta = \frac{1-\cos 2\theta}{2}, recompose: use it to evaluate ∫sin⁑2θ dΞΈ\int \sin^2\theta\, d\theta.

Example 3

easy
You found two rectangle areas 1212 and 88 that make an L-shape. What is the total area?

Example 4

easy
Partial fractions gave 1xβˆ’1+1x+1\frac{1}{x-1}+\frac{1}{x+1}. Recombine into a single fraction.

Example 5

easy
You computed 7Γ—10=707\times10=70 and 7Γ—2=147\times2=14. Recombine for 7Γ—127\times12.

Example 6

easy
Two trip legs took 22 h and 11 h. Recombine for total time.

Example 7

easy
You found roots u=2u=2 and u=3u=3 for u=xu=\sqrt x. Recombine to get the xx-solutions.

Example 8

easy
Place-value pieces 100+20+3100+20+3 recombine to what number?

Example 9

easy
A cylinder volume is Ο€r2h\pi r^2 h and a removed cone is 13Ο€r2h\frac13\pi r^2 h. Recombine (subtract) for the remaining volume.

Example 10

easy
You split ∫(2x+cos⁑x)dx\int(2x+\cos x)dx into x2x^2 and sin⁑x\sin x. Recombine the antiderivative.

Example 11

medium
Two overlapping sets have ∣A∣=10|A|=10, ∣B∣=8|B|=8, ∣A∩B∣=3|A\cap B|=3. Recombine for ∣AβˆͺB∣|A\cup B|.

Example 12

medium
Sub-sums βˆ‘k2=n(n+1)(2n+1)6\sum k^2=\frac{n(n+1)(2n+1)}{6} and βˆ‘k=n(n+1)2\sum k=\frac{n(n+1)}{2} were found. Recombine for βˆ‘(k2+k)\sum (k^2+k) at n=3n=3.

Example 13

medium
A complex number was split as z=3+4iz=3+4i. Recombine to find its modulus ∣z∣|z|.

Example 14

medium
Vector components ⟨3,0⟩\langle 3,0\rangle and ⟨0,4⟩\langle0,4\rangle were found. Recombine into one vector and give its magnitude.

Example 15

medium
A region's area was split as the integral ∫01x dx\int_0^1 x\,dx minus ∫01x2 dx\int_0^1 x^2\,dx. Recombine to a number.

Example 16

medium
Modular sub-results x≑2(mod3)x\equiv2\pmod3 and x≑3(mod5)x\equiv3\pmod5 were found. Recombine via CRT for the smallest positive xx.

Example 17

challenge
Solving a system, you found x=2x=2 from one equation and need yy. Given 2x+y=72x+y=7, recombine to finish, then verify in xβˆ’y=βˆ’1x-y=-1.

Example 18

challenge
Pieces of a piecewise function: f(x)=x2f(x)=x^2 for x≀1x\le1 and f(x)=2xβˆ’1f(x)=2x-1 for x>1x>1. Recombine and check continuity at x=1x=1.

Example 19

challenge
After decomposing 2xx2βˆ’1=1xβˆ’1+1x+1\frac{2x}{x^2-1}=\frac{1}{x-1}+\frac{1}{x+1}, recombine into ∫2xx2βˆ’1dx\int\frac{2x}{x^2-1}dx.

Example 20

medium
Cases x=8x=8 and x=βˆ’2x=-2 solve an absolute-value equation. Recombine into the solution set.

Example 21

medium
Digit-stage counts 9,9,89,9,8 were found for distinct-digit 33-digit numbers. Recombine for the total.

Example 22

medium
A trapezoid was split into a rectangle (area bhbh) and a triangle (area (aβˆ’b)h2\frac{(a-b)h}{2}, with a>ba>b). Recombine into one formula.

Example 23

easy
After factoring x2βˆ’9=(xβˆ’3)(x+3)x^2 - 9 = (x-3)(x+3), recompose to solve x2βˆ’9=0x^2 - 9 = 0.

Example 24

easy
Distance pieces: 4Β kmΒ north4\text{ km north} then 3Β kmΒ east3\text{ km east}. Recompose for straight-line distance from start.

Example 25

easy
Partial fractions yielded 2xβˆ’2x+1\frac{2}{x} - \frac{2}{x+1}. Recombine into a single fraction.

Example 26

easy
Sub-results sin⁑θ=3/5\sin\theta = 3/5 and cos⁑θ=4/5\cos\theta = 4/5. Recombine for tan⁑θ\tan\theta.

Example 27

medium
After splitting ∫(3x2+4x) dx\int (3x^2 + 4x)\,dx into ∫3x2 dx\int 3x^2\,dx and ∫4x dx\int 4x\,dx, recombine the antiderivative.

Example 28

medium
Vector components ⟨5,12⟩\langle 5, 12\rangle were found from a problem. Recombine into the vector's magnitude.

Example 29

medium
Sub-counts: 44 shirts and 33 pants. Recombine for the number of outfits (one of each).

Example 30

medium
Two probabilities found: P(A)=0.4P(A) = 0.4, P(B)=0.5P(B) = 0.5 with A,BA,B independent. Recombine for P(A∩B)P(A \cap B).

Example 31

medium
Solving a system in two pieces, you found x=4x = 4 from elimination, then needed yy. Substituting into 3x+2y=163x + 2y = 16, recombine for yy.

Example 32

hard
A region between y=x2y=x^2 and y=4y=4 was split into left and right halves by symmetry, each with area 163\frac{16}{3}. Recompose for the total area.

Example 33

hard
A solid is decomposed: a cylinder of volume 40Ο€40\pi minus a hemisphere of volume 163Ο€\frac{16}{3}\pi scooped out. Recombine for the remaining volume.

Example 34

hard
Solving ∣2xβˆ’1∣=5|2x - 1| = 5, two cases gave x=3x = 3 and x=βˆ’2x = -2. Recompose the solution set and verify.

Example 35

hard
After computing fβ€²(x)=2xf'(x) = 2x from f(x)=x2+5f(x) = x^2 + 5, recompose by integrating fβ€²f' to recover ff (up to a constant).

Example 36

challenge
A piecewise function: f(x)=xf(x) = x for x≀0x \le 0, f(x)=x2f(x) = x^2 for x>0x > 0. Recompose: is ff continuous at 00?

Example 37

challenge
Eigenvalues of a 2Γ—22\times2 matrix are Ξ»1=3,Ξ»2=5\lambda_1 = 3, \lambda_2 = 5. Recombine for the determinant and trace.

Related Concepts

Background Knowledge

These ideas may be useful before you work through the harder examples.

decomposition meta