Range Math Example 1

Solution

1. 1
   Since $x^2 \geq 0$ for all real $x$, the minimum value of $x^2$ is $0$.
2. 2
   Therefore $f(x) = x^2 + 1 \geq 0 + 1 = 1$.
3. 3
   As $x \to \pm\infty$, $f(x) \to \infty$, so the range is $[1, \infty)$.