Quantifiers Examples: 47 Problems with Answers

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Quantifiers.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Symbols specifying the scope of a predicate: ∀ (for all, universal) and ∃ (there exists, existential).

∀ means 'for all' (everyone). ∃ means 'there exists' (at least one).

Read the full concept explanation →

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Quantifiers set the scope of a predicate: every case (∀) or at least one case (∃).

Common stuck point: The procedure for quantifiers is the easy part; the trap is negating 'for all' as 'for none'. Asking "Am I claiming a property for every element or for at least one element?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Am I claiming a property for every element or for at least one element?

Worked Examples

Example 1

easy
Translate into symbols and determine the truth value: (a) 'Every natural number is positive.', (b) 'There exists a real number x such that x2=2.'

Answer

(a)  ∀n∈N,  n>0  (True under N={1,2,…}),(b)  ∃x∈R,  x2=2  (True)

First step

1
The universal quantifier ∀ means 'for all'; the existential quantifier ∃ means 'there exists at least one.'

Full solution

  1. 2
    Translate: (a) 'Every natural number is positive' → ∀n∈N,  n>0. (b) 'There exists a real number x such that x2=2' → ∃x∈R,  x2=2.
  2. 3
    Truth values: (a) True under the convention N={1,2,3,…} since all such n≥1>0. (If 0∈N, the statement is False.) (b) True: x=2∈R satisfies (2)2=2.
The universal quantifier ∀ requires the predicate to hold for every element. The existential quantifier ∃ requires at least one element satisfying the predicate. Truth values may depend on the domain.

Example 2

medium
Negate the statement ∀x∈R,  x2≥0 and determine the truth value of both the original and its negation.

Example 3

easy
Write the negation of 'Every car in the lot is red' in plain English.

Example 4

medium
Translate, then determine truth over R: 'For every positive real x there is a positive real y with y<x.'

Example 5

medium
Decide and justify over R: '∀x, ∃y, y2=x.'

Example 6

hard
Translate 'there is no largest integer' two ways: (a) with ¬∃, (b) with ∀∃.

Example 7

challenge
State formally that f:R→R is not uniformly continuous on R, by negating: ∀ε>0, ∃δ>0, ∀x,y, ∣x−y∣<δ→∣f(x)−f(y)∣<ε.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Write in words: (a) ∀x∈Z,  x+0=x, (b) ∃x∈N,  x<5.

Example 2

medium
Determine the truth value of each and write its negation: (a) ∀x∈R,  x>0, (b) ∃x∈Z,  x2=3.

Example 3

easy
What does the symbol ∀ mean?

Example 4

easy
What does the symbol ∃ mean?

Example 5

easy
Negate the statement '∀x, P(x)'.

Example 6

easy
Negate the statement '∃x, P(x)'.

Example 7

easy
Is '∀x∈R, x2≥0' true or false?

Example 8

easy
Is '∃x∈R, x2=−1' true or false?

Example 9

easy
Translate 'every prime greater than 2 is odd' into quantifier notation (let P(x) = 'x is prime', x>2).

Example 10

easy
In the statement '∃x, x+3=5' over the integers, which x witnesses the existential?

Example 11

medium
Negate: '∀x, ∃y, x+y=0'. Push the negation all the way in.

Example 12

medium
Are '∀x ∃y, y>x' and '∃y ∀x, y>x' equivalent over the reals? State which (if any) is true.

Example 13

medium
Negate 'every student passed the exam' and express it in plain English.

Example 14

medium
Translate 'there is a smallest positive integer' using quantifiers (domain: positive integers, ≤).

Example 15

medium
Is the universal statement '∀n∈N, n2+n+41 is prime' true? Justify.

Example 16

medium
Rewrite 'no real number satisfies x2<0' with a quantifier, then give the equivalent universal form.

Example 17

medium
In '∀ε>0, ∃δ>0, ∣x−a∣<δ→∣f(x)−f(a)∣<ε', does δ depend on ε?

Example 18

medium
Translate 'some integer is both even and odd' and decide its truth value.

Example 19

medium
Translate 'every nonzero real has a multiplicative inverse' into quantifier notation over R.

Example 20

challenge
Negate the limit definition '∀ε>0, ∃δ>0, ∀x, (0<∣x−a∣<δ→∣f(x)−L∣<ε)' fully.

Example 21

challenge
For predicate P(x,y), when is '∀x ∃y P(x,y)' true but '∃y ∀x P(x,y)' false? Give a concrete P over Z.

Example 22

challenge
Express 'there is exactly one x with P(x)' using ∃, ∀, and equality.

Example 23

easy
Translate into symbols: 'For every real number x, x+1>x.'

Example 24

easy
Translate into symbols: 'There exists an integer whose square is 9.'

Example 25

easy
True or false over R: ∃x, x2=2.

Example 26

easy
True or false over Z: ∀n, 2n is even.

Example 27

easy
Give a witness that makes '∃x∈Z, x2−4=0' true.

Example 28

medium
Negate and simplify: '∀x∈R, (x>0→x2>0).'

Example 29

medium
Are '∀x∃y, y=x+1' and '∃y∀x, y=x+1' equivalent over Z? Briefly justify.

Example 30

medium
Translate: 'Every nonempty set of positive integers has a least element' using ∀,∃,∈.

Example 31

medium
Disprove '∀n∈N, n2≥2n' by giving a counterexample or show it is true.

Example 32

medium
Translate: 'No prime greater than 2 is even' using a universal quantifier.

Example 33

medium
Negate, pushing ¬ inward: '∃x∀y, x≤y' over Z.

Example 34

medium
Translate: 'The function f is surjective from A to B' using quantifiers.

Example 35

medium
Translate: 'f is injective on A' using quantifiers.

Example 36

medium
Translate 'every integer is even or odd' and write its negation.

Example 37

hard
Negate the convergence statement '∀ε>0, ∃N∈N, ∀n≥N, ∣an−L∣<ε.'

Example 38

hard
Over R, decide and justify: '∃x, ∀y, x+y>y.'

Example 39

hard
Let P(x,y) be 'x divides y' on Z+. Decide truth: (a) ∀y, ∃x, P(x,y); (b) ∃x, ∀y, P(x,y).

Example 40

challenge
Translate uniqueness '∃!x, P(x)' using only ∃,∀,→,=.

Background Knowledge

These ideas may be useful before you work through the harder examples.

logical statement