Quadrilateral Hierarchy Math Example 4

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Example 4

hard
In parallelogram ABCDABCD, A=3x+15°\angle A = 3x + 15° and B=5x5°\angle B = 5x - 5°. Find all four angles. Use the property that consecutive angles in a parallelogram are supplementary.

Solution

  1. 1
    Step 1: In a parallelogram, consecutive angles are supplementary: A+B=180°\angle A + \angle B = 180°. So (3x+15)+(5x5)=180(3x+15) + (5x-5) = 180.
  2. 2
    Step 2: 8x+10=1808x + 10 = 180, so 8x=1708x = 170, giving x=21.25x = 21.25.
  3. 3
    Step 3: A=3(21.25)+15=63.75+15=78.75°\angle A = 3(21.25) + 15 = 63.75 + 15 = 78.75°. B=5(21.25)5=106.255=101.25°\angle B = 5(21.25) - 5 = 106.25 - 5 = 101.25°.
  4. 4
    Step 4: In a parallelogram, opposite angles are equal: C=A=78.75°\angle C = \angle A = 78.75° and D=B=101.25°\angle D = \angle B = 101.25°. Check: 78.75+101.25+78.75+101.25=360°78.75 + 101.25 + 78.75 + 101.25 = 360°. ✓

Answer

A=C=78.75°\angle A = \angle C = 78.75°; B=D=101.25°\angle B = \angle D = 101.25°.
Parallelograms have two key angle properties: opposite angles are equal, and consecutive angles are supplementary. Using these properties with algebraic expressions allows you to find all four angles. The total always equals 360°, consistent with the quadrilateral angle sum.

About Quadrilateral Hierarchy

The quadrilateral hierarchy organizes four-sided polygons by their properties in a classification tree. Every square is a rectangle, every rectangle is a parallelogram, and every parallelogram is a trapezoid — each level adds constraints like equal sides or right angles.

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