Quadratic Vertex Form Math Example 3

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Example 3

easy
What is the vertex of g(x)=โˆ’(x+5)2โˆ’2g(x) = -(x + 5)^2 - 2?

Solution

  1. 1
    Rewrite as g(x)=โˆ’(xโˆ’(โˆ’5))2+(โˆ’2)g(x) = -(x - (-5))^2 + (-2).
  2. 2
    Vertex: (โˆ’5,โˆ’2)(-5, -2). The parabola opens downward (a=โˆ’1<0a = -1 < 0).

Answer

(โˆ’5,โˆ’2)(-5, -2)
Be careful with signs: (x+5)=(xโˆ’(โˆ’5))(x + 5) = (x - (-5)), so h=โˆ’5h = -5.

About Quadratic Vertex Form

A quadratic written as f(x)=a(xโˆ’h)2+kf(x) = a(x - h)^2 + k, where the vertex (h,k)(h, k) is directly readable from the formula.

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