Proof (Intuition) Math Example 3

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Example 3

easy
Build intuition for the statement: 'For any integer nn, n(n+1)n(n+1) is even.' Explain informally why this must be true.

Solution

  1. 1
    Intuition: among any two consecutive integers nn and n+1n+1, one must be even and one odd.
  2. 2
    An even number times any integer is even. So n(n+1)n(n+1) always contains at least one even factor.
  3. 3
    Formal check: if nn is even, n=2kn = 2k, so n(n+1)=2k(n+1)n(n+1) = 2k(n+1) is even. If nn is odd, n+1n+1 is even, so again the product is even.

Answer

n(n+1) is always even — one of any two consecutive integers is evenn(n+1) \text{ is always even — one of any two consecutive integers is even}
The intuition ('consecutive integers include one even') both explains the result and points directly to the case-split needed in the formal proof.

About Proof (Intuition)

The informal, intuitive sense of why a mathematical statement must be true — the "aha" that precedes and motivates a formal proof.

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