Projection Math Example 4

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Example 4

hard
Project the vector vโƒ—=(2,โˆ’1,3)\vec{v} = (2, -1, 3) onto the unit vector u^=(0,0,1)\hat{u} = (0, 0, 1) (the zz-axis direction). Interpret the result geometrically.

Solution

  1. 1
    Step 1: Scalar projection =vโƒ—โ‹…u^=(2)(0)+(โˆ’1)(0)+(3)(1)=3= \vec{v} \cdot \hat{u} = (2)(0)+(-1)(0)+(3)(1) = 3.
  2. 2
    Step 2: Vector projection =3u^=3(0,0,1)=(0,0,3)= 3\hat{u} = 3(0,0,1) = (0, 0, 3).

Answer

Projection =(0,0,3)= (0, 0, 3), the zz-component of vโƒ—\vec{v}.
Projecting onto a coordinate axis extracts that coordinate. The projection of (2,โˆ’1,3)(2,-1,3) onto the zz-axis gives (0,0,3)(0,0,3), showing that the zz-component =3=3 is the 'shadow' of the vector on the zz-axis. The remaining part (2,โˆ’1,0)(2,-1,0) is perpendicular to the zz-axis.

About Projection

The image formed when points of a shape are mapped onto a lower-dimensional surface along parallel or converging rays.

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