Polygon Math Example 2

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Example 2

medium
Each interior angle of a regular polygon is 150°150°. How many sides does it have?

Solution

  1. 1
    Step 1: For a regular polygon, each interior angle =(n2)×180°n= \dfrac{(n-2) \times 180°}{n}.
  2. 2
    Step 2: Set equal to 150°150°: (n2)×180n=150\dfrac{(n-2) \times 180}{n} = 150.
  3. 3
    Step 3: Multiply both sides by nn: (n2)×180=150n(n-2) \times 180 = 150n.
  4. 4
    Step 4: Expand and solve: 180n360=150n30n=360n=12180n - 360 = 150n \Rightarrow 30n = 360 \Rightarrow n = 12.

Answer

12 sides (regular dodecagon)
By setting the regular polygon interior angle formula equal to the given angle and solving, we find the number of sides. Alternatively, each exterior angle =180°150°=30°= 180° - 150° = 30°, and the sum of exterior angles is always 360°360°, so n=360°/30°=12n = 360°/30° = 12.

About Polygon

A closed two-dimensional figure formed by three or more straight line segments connected end-to-end.

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