Perpendicularity Math Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
Line โ„“1:y=2x+1\ell_1: y = 2x + 1. Write the equation of a line โ„“2\ell_2 perpendicular to โ„“1\ell_1 that passes through (4,3)(4, 3).

Solution

  1. 1
    Step 1: Slope of โ„“1\ell_1: m1=2m_1 = 2.
  2. 2
    Step 2: Perpendicular slope: m2=โˆ’1m1=โˆ’12m_2 = -\dfrac{1}{m_1} = -\dfrac{1}{2} (since m1ร—m2=โˆ’1m_1 \times m_2 = -1).
  3. 3
    Step 3: Point-slope form: yโˆ’3=โˆ’12(xโˆ’4)โ‡’y=โˆ’12x+5y - 3 = -\dfrac{1}{2}(x - 4) \Rightarrow y = -\dfrac{1}{2}x + 5.

Answer

y=โˆ’12x+5y = -\dfrac{1}{2}x + 5
Perpendicular lines meet at 90ยฐ90ยฐ. Their slopes are negative reciprocals: if one slope is mm, the other is โˆ’1/m-1/m. This ensures m1ร—m2=โˆ’1m_1 \times m_2 = -1.

About Perpendicularity

Lines, segments, or planes that intersect at exactly a right angle of 90ยฐ90ยฐ to each other.

Learn more about Perpendicularity โ†’

More Perpendicularity Examples