Perimeter Math Example 4

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Example 4

medium
The length of a rectangle is 33 m more than twice its width. If its perimeter is 4242 m, find the length and width.

Solution

  1. 1
    Let the width be ww m. Then the length is 2w+32w + 3 m, and the perimeter equation is 2l+2w=422l + 2w = 42.
  2. 2
    Substitute: 2(2w+3)+2w=42⇒4w+6+2w=42⇒6w=362(2w + 3) + 2w = 42 \Rightarrow 4w + 6 + 2w = 42 \Rightarrow 6w = 36.
  3. 3
    So w=6w = 6 m, and the length is 2(6)+3=152(6) + 3 = 15 m.

Answer

Width=6 m,Length=15 m\text{Width} = 6 \text{ m}, \quad \text{Length} = 15 \text{ m}
Perimeter descriptions often turn into algebra equations when one side depends on another. Once the side expressions are written correctly, the perimeter formula gives the missing dimensions.

About Perimeter

The total distance around the outside of a two-dimensional shape, found by adding all its side lengths.

Learn more about Perimeter →

More Perimeter Examples

Example 1 easy

Find the perimeter of a rectangle with length [formula] cm and width [formula] cm.

Example 2 medium

A triangle has sides measuring [formula] cm, [formula] cm, and [formula] cm. Find its perimeter.

Example 3 easy

Find the perimeter of a square with side length [formula] m.

← All Perimeter Examples Perimeter Concept