Parallel and Perpendicular Math Example 3

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Example 3

easy
Are the lines y=โˆ’4x+1y = -4x + 1 and y=14xโˆ’3y = \frac{1}{4}x - 3 parallel, perpendicular, or neither?

Solution

  1. 1
    Slopes: m1=โˆ’4m_1 = -4 and m2=14m_2 = \dfrac{1}{4}.
  2. 2
    Check product: m1ร—m2=โˆ’4ร—14=โˆ’1m_1 \times m_2 = -4 \times \dfrac{1}{4} = -1. Since the product is โˆ’1-1, the lines are perpendicular.

Answer

The lines are perpendicular.
Two lines are perpendicular when the product of their slopes is โˆ’1-1. Two lines are parallel when their slopes are equal. Here (โˆ’4)(14)=โˆ’1(-4)(\frac{1}{4}) = -1, confirming the lines meet at right angles.

About Parallel and Perpendicular

Parallel lines never intersect and have matching direction; perpendicular lines intersect at right angles.

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