Noise Math Example 3

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Example 3

easy
A thermometer in a stable environment reads: {20.1,19.9,20.2,20.0,19.8}\{20.1, 19.9, 20.2, 20.0, 19.8\}°C. The true temperature is 20°C. Calculate the noise (variability) and explain how taking more measurements would help.

Solution

  1. 1
    Mean: xˉ=20.0\bar{x} = 20.0°C (correct!); this is the signal
  2. 2
    Range of noise: 20.219.8=0.420.2 - 19.8 = 0.4°C; individual readings vary by ±0.2°C
  3. 3
    More measurements: standard error = σn\frac{\sigma}{\sqrt{n}}; with more nn, the mean becomes more stable, reducing the effect of noise on our estimate

Answer

Noise range = 0.4°C. More readings reduce the uncertainty in the mean estimate.
Random noise is reduced by averaging. The standard error of the mean decreases as 1/n1/\sqrt{n}, so quadrupling the number of measurements halves the noise in the estimated mean.

About Noise

Noise is random variation in data that is not explained by the underlying pattern or model — the unpredictable fluctuations around the true signal.

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