Practice Mathematical Induction in Math

Use these practice problems to test your method after reviewing the concept explanation and worked examples.

Quick Recap

Mathematical induction proves statements indexed by integers by verifying a base case and an inductive step.

Like dominoes: first one falls, and each one knocks over the next.

Showing a random 20 of 50 problems.

Example 1

medium
Inductive step for '3∣(n3βˆ’n)3 \mid (n^3 - n) for all nβ‰₯0n\ge0'.

Example 2

medium
Prove by induction: 7∣(8nβˆ’1)7 \mid (8^n - 1) for all nβ‰₯1n\ge 1.

Example 3

easy
For which kind of statement is induction the right tool?

Example 4

medium
Prove by induction: 5∣(n5βˆ’n)5 \mid (n^5 - n) for all nβ‰₯0n\ge 0.

Example 5

easy
What is wrong with 'proving' a claim about real numbers by induction on the real number xx?

Example 6

easy
Verify the base case n=1n=1 for '1+2+β‹―+n=n(n+1)21+2+\cdots+n = \frac{n(n+1)}{2}'.

Example 7

easy
For the claim 'n2β‰₯nn^2 \ge n for all integers nβ‰₯0n \ge 0,' which base case should you check?

Example 8

medium
Prove by induction: βˆ‘i=1niβ‹…2i=(nβˆ’1)2n+1+2\sum_{i=1}^n i \cdot 2^{i} = (n-1)2^{n+1}+2 for nβ‰₯1n\ge 1.

Example 9

hard
Prove by induction: n2<2nn^2 < 2^n for all nβ‰₯5n\ge 5.

Example 10

easy
What goes wrong if you prove the inductive step but skip the base case?

Example 11

hard
Prove by induction: βˆ‘i=1n1i(i+1)=nn+1\sum_{i=1}^n \tfrac{1}{i(i+1)} = \tfrac{n}{n+1} for nβ‰₯1n\ge 1.

Example 12

medium
Use strong induction to prove every integer nβ‰₯2n\ge 2 has a prime factorization.

Example 13

easy
Name the two things you must do in an inductive proof.

Example 14

easy
Compute both sides of '1+2+3=3β‹…421+2+3 = \frac{3\cdot4}{2}' to confirm the formula at n=3n=3.

Example 15

challenge
Prove by induction: n3+2nn^3 + 2n is divisible by 3 for all nβ‰₯0n\ge0.

Example 16

hard
Prove by induction: the Fibonacci numbers satisfy Fn+1Fnβˆ’1βˆ’Fn2=(βˆ’1)nF_{n+1}F_{n-1} - F_n^2 = (-1)^n for nβ‰₯1n\ge 1 (Cassini's identity).

Example 17

easy
State precisely what the principle of mathematical induction allows you to conclude after verifying the base case P(1)P(1) and the implication P(k)β‡’P(k+1)P(k)\Rightarrow P(k+1).

Example 18

medium
Inductive step for 'βˆ‘i=1n2iβˆ’1=2nβˆ’1\sum_{i=1}^n 2^{i-1} = 2^n - 1' (sum of powers of 2).

Example 19

medium
Why is the base case here n=5n=5 for '2n>n22^n > n^2' rather than n=1n=1?

Example 20

easy
Write down the inductive hypothesis for proving '3∣(4nβˆ’1)3\mid (4^n - 1) for all nβ‰₯1n\ge 1.'