Lines in 3D Math Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
Write parametric equations for the line through the point (2,โˆ’1,3)(2, -1, 3) in the direction of the vector โŸจ4,1,โˆ’2โŸฉ\langle 4, 1, -2 \rangle.

Solution

  1. 1
    The parametric equations for a line through (x0,y0,z0)(x_0, y_0, z_0) with direction vector โŸจa,b,cโŸฉ\langle a, b, c \rangle are: x=x0+atx = x_0 + at, y=y0+bty = y_0 + bt, z=z0+ctz = z_0 + ct.
  2. 2
    Substitute: x=2+4tx = 2 + 4t, y=โˆ’1+ty = -1 + t, z=3โˆ’2tz = 3 - 2t.
  3. 3
    Verify: at t=0t = 0, the point is (2,โˆ’1,3)(2, -1, 3) โœ“, and the direction is โŸจ4,1,โˆ’2โŸฉ\langle 4, 1, -2 \rangle โœ“.

Answer

x=2+4t,y=โˆ’1+t,z=3โˆ’2tx = 2 + 4t, \quad y = -1 + t, \quad z = 3 - 2t
A line in 3D is determined by a point and a direction vector. Parametric form represents each coordinate as a linear function of the parameter tt. As tt varies over all real numbers, the equations trace the entire line.

About Lines in 3D

Lines in three-dimensional space described using parametric equations x=x0+atx = x_0 + at, y=y0+bty = y_0 + bt, z=z0+ctz = z_0 + ct, or symmetric form xโˆ’x0a=yโˆ’y0b=zโˆ’z0c\frac{x - x_0}{a} = \frac{y - y_0}{b} = \frac{z - z_0}{c}, where (x0,y0,z0)(x_0, y_0, z_0) is a point on the line and โŸจa,b,cโŸฉ\langle a, b, c \rangle is the direction vector.

Learn more about Lines in 3D โ†’

More Lines in 3D Examples