Limit Math Example 5

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Example 5

medium
Find limโกxโ†’โˆ’1x2+3x+2x+1\lim_{x \to -1} \frac{x^2 + 3x + 2}{x + 1}

Solution

  1. 1
    Direct substitution: (โˆ’1)2+3(โˆ’1)+2โˆ’1+1=00\frac{(-1)^2 + 3(-1) + 2}{-1 + 1} = \frac{0}{0}, indeterminate.
  2. 2
    Factor the numerator: x2+3x+2=(x+1)(x+2)x^2 + 3x + 2 = (x + 1)(x + 2).
  3. 3
    Cancel: (x+1)(x+2)x+1=x+2\frac{(x+1)(x+2)}{x+1} = x + 2 for xโ‰ โˆ’1x \neq -1.
  4. 4
    Evaluate: limโกxโ†’โˆ’1(x+2)=1\lim_{x \to -1} (x + 2) = 1.

Answer

11
Factor and cancel the common factor that causes the 00\frac{0}{0} form, then substitute.

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