Least Common Multiple Math Example 2

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Example 2

medium
Find the LCM of 88, 1212, and 1515.

Solution

  1. 1
    Prime factorizations: 8=238 = 2^3, 12=22Γ—312 = 2^2 \times 3, 15=3Γ—515 = 3 \times 5.
  2. 2
    Take the maximum exponent of each prime: 23Γ—31Γ—51=8Γ—3Γ—52^3 \times 3^1 \times 5^1 = 8 \times 3 \times 5.
  3. 3
    Compute: 8Γ—3=248 \times 3 = 24, then 24Γ—5=12024 \times 5 = 120.

Answer

120120
For multiple numbers, find all primes that appear in any factorization and take the highest power of each. The LCM is essential for adding fractions with different denominators.

About Least Common Multiple

The smallest positive integer that is divisible by each of two or more given numbersβ€”where their multiples first coincide.

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