Inverse Matrix Math Example 1

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Example 1

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Find the inverse of A=[2153]A = \begin{bmatrix} 2 & 1 \\ 5 & 3 \end{bmatrix}.

Solution

  1. 1
    Step 1: detโก(A)=2(3)โˆ’1(5)=6โˆ’5=1\det(A) = 2(3) - 1(5) = 6 - 5 = 1.
  2. 2
    Step 2: Swap aa and dd, negate bb and cc: 11[3โˆ’1โˆ’52]\frac{1}{1}\begin{bmatrix} 3 & -1 \\ -5 & 2 \end{bmatrix}.
  3. 3
    Step 3: Aโˆ’1=[3โˆ’1โˆ’52]A^{-1} = \begin{bmatrix} 3 & -1 \\ -5 & 2 \end{bmatrix}.
  4. 4
    Check: AAโˆ’1=[6โˆ’5โˆ’2+215โˆ’15โˆ’5+6]=[1001]AA^{-1} = \begin{bmatrix} 6-5 & -2+2 \\ 15-15 & -5+6 \end{bmatrix} = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} โœ“

Answer

[3โˆ’1โˆ’52]\begin{bmatrix} 3 & -1 \\ -5 & 2 \end{bmatrix}
The 2ร—22 \times 2 inverse formula swaps the diagonal entries, negates the off-diagonal entries, and divides by the determinant. The check AAโˆ’1=IAA^{-1} = I confirms correctness.

About Inverse Matrix

The inverse of a square matrix AA, written Aโˆ’1A^{-1}, is the unique matrix such that AAโˆ’1=Aโˆ’1A=IAA^{-1} = A^{-1}A = I (the identity matrix). A matrix has an inverse if and only if its determinant is nonzero.

Learn more about Inverse Matrix โ†’

More Inverse Matrix Examples