Invariants Math Example 1

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Example 1

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A sequence starts at 1 and each term is 3 times the previous minus 2: \(a_{n+1} = 3a_n - 2\). Show that the quantity \(a_n - 1\) grows by a factor of 3 each step (i.e., \(a_n - 1 = 3^{n-1}(a_1 - 1)\) is an invariant structure).

Solution

  1. 1
    Define \(b_n = a_n - 1\). Then \(b_{n+1} = a_{n+1} - 1 = (3a_n - 2) - 1 = 3a_n - 3 = 3(a_n-1) = 3b_n\).
  2. 2
    So \(b_n\) forms a geometric sequence: \(b_n = b_1 \cdot 3^{n-1}\).
  3. 3
    With \(a_1=1\): \(b_1 = 0\), so \(b_n = 0\) for all \(n\), meaning \(a_n = 1\) for all \(n\).
  4. 4
    Invariant: if \(a_1=1\), the fixed point \(a=1\) is preserved.

Answer

\(a_n = 1\) for all \(n\); fixed point is an invariant
An invariant is a quantity that doesn't change under the transformation. Here \(a_n = 1\) is a fixed point of the recurrence — once there, the sequence stays.

About Invariants

Quantities or properties that remain unchanged during a process, operation, or transformation—values that stay the same no matter how the system is rearranged or acted upon.

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