Invariants Under Transformation Math Example 4

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Example 4

hard
Under a shear transformation defined by (x,y)(x+2y,y)(x, y) \to (x + 2y, y), determine whether the area of a unit square with vertices (0,0)(0,0), (1,0)(1,0), (1,1)(1,1), (0,1)(0,1) is preserved.

Solution

  1. 1
    Apply the shear to each vertex: (0,0)(0,0)(0,0) \to (0,0), (1,0)(1,0)(1,0) \to (1,0), (1,1)(3,1)(1,1) \to (3,1), (0,1)(2,1)(0,1) \to (2,1). The image is a parallelogram.
  2. 2
    The area of the parallelogram can be found using the cross product of two edge vectors: u=(1,0)\vec{u} = (1,0) and v=(2,1)\vec{v} = (2,1). Area =1102=1= |1 \cdot 1 - 0 \cdot 2| = 1. The area equals the original, so area IS invariant under this shear.

Answer

Yes, the area is invariant. The sheared parallelogram has area 1.\text{Yes, the area is invariant. The sheared parallelogram has area } 1.
Shear transformations have a transformation matrix with determinant 11 (since det(1201)=1\det\begin{pmatrix}1&2\\0&1\end{pmatrix}=1). Any linear transformation with det=1|\det|=1 preserves area. Shears change shape but not area — they are area-preserving but not distance-preserving.

About Invariants Under Transformation

A property of a function is invariant under a transformation if it remains unchanged after the transformation is applied to the function.

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