Improper Integrals Math Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

easy
Does โˆซ1โˆž1xโ€‰dx\displaystyle\int_1^{\infty} \frac{1}{x}\,dx converge or diverge?

Solution

  1. 1
    limโกbโ†’โˆž[lnโกx]1b=limโกbโ†’โˆžlnโกb=โˆž\lim_{b\to\infty}[\ln x]_1^b = \lim_{b\to\infty}\ln b = \infty. Diverges.

Answer

Diverges.
lnโกbโ†’โˆž\ln b \to \infty, so no finite limit exists. This is the integral analog of the divergent harmonic series.

About Improper Integrals

Integrals where the interval of integration is infinite (Type I: โˆซaโˆžf(x)โ€‰dx\int_a^{\infty} f(x)\,dx) or the integrand has an infinite discontinuity on the interval (Type II: โˆซabf(x)โ€‰dx\int_a^b f(x)\,dx where ff blows up at some point in [a,b][a, b]). Evaluated as limits of proper integrals.

Learn more about Improper Integrals โ†’

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