Empty Set Math Example 4

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Example 4

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Let A=โˆ…A = \emptyset. Find: (a) AโˆชBA \cup B for any set BB, (b) AโˆฉBA \cap B for any set BB, (c) P(A)\mathcal{P}(A) (the power set of AA).

Solution

  1. 1
    (a) โˆ…โˆชB=B\emptyset \cup B = B. Adding no elements to BB leaves BB unchanged.
  2. 2
    (b) โˆ…โˆฉB=โˆ…\emptyset \cap B = \emptyset. There are no elements in โˆ…\emptyset, so the intersection is empty.
  3. 3
    (c) P(โˆ…)={โˆ…}\mathcal{P}(\emptyset) = \{\emptyset\}. The only subset of โˆ…\emptyset is โˆ…\emptyset itself, so the power set has one element.

Answer

(a)โ€…โ€ŠB,(b)โ€…โ€Šโˆ…,(c)โ€…โ€Š{โˆ…}(a)\;B,\quad (b)\;\emptyset,\quad (c)\;\{\emptyset\}
The empty set is an identity element for union and an absorbing element for intersection. Its power set {โˆ…}\{\emptyset\} has exactly one element, so โˆฃP(โˆ…)โˆฃ=1=20|\mathcal{P}(\emptyset)| = 1 = 2^0.

About Empty Set

The empty set, denoted โˆ…\emptyset or {}\{\}, is the unique set that contains no elements at all. It is a subset of every set because the statement 'every element of โˆ…\emptyset belongs to AA' is vacuously true โ€” there are no elements to contradict it.

Learn more about Empty Set โ†’

More Empty Set Examples