Distance Formula Math Example 1

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Example 1

easy
Find the distance between the points (1,2)(1, 2) and (4,6)(4, 6).

Solution

  1. 1
    The distance formula is derived from the Pythagorean theorem: the horizontal and vertical separations form the legs of a right triangle, and the distance is the hypotenuse. d=(x2โˆ’x1)2+(y2โˆ’y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.
  2. 2
    Identify the coordinates: (x1,y1)=(1,2)(x_1, y_1) = (1, 2) and (x2,y2)=(4,6)(x_2, y_2) = (4, 6). Compute the differences: x2โˆ’x1=3x_2 - x_1 = 3, y2โˆ’y1=4y_2 - y_1 = 4.
  3. 3
    Substitute: d=32+42=9+16=25=5d = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5. Recognise the 3-4-5 Pythagorean triple โ€” no calculator needed.

Answer

d=5d = 5
The distance formula is a direct application of the Pythagorean theorem on the coordinate plane. The horizontal and vertical differences form the legs of a right triangle, and the distance is the hypotenuse.

About Distance Formula

A formula for finding the distance between two points in the coordinate plane, derived directly from the Pythagorean theorem.

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