Decomposition Math Example 2

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Example 2

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Decompose the partial fraction 5x+1(x+1)(xโˆ’2)\dfrac{5x+1}{(x+1)(x-2)} into the form Ax+1+Bxโˆ’2\dfrac{A}{x+1} + \dfrac{B}{x-2}.

Solution

  1. 1
    Write 5x+1(x+1)(xโˆ’2)=Ax+1+Bxโˆ’2\frac{5x+1}{(x+1)(x-2)} = \frac{A}{x+1} + \frac{B}{x-2}. Multiply both sides by (x+1)(xโˆ’2)(x+1)(x-2): 5x+1=A(xโˆ’2)+B(x+1)5x+1 = A(x-2)+B(x+1).
  2. 2
    Set x=2x=2: 11=3B11 = 3B, so B=113B = \frac{11}{3}. Set x=โˆ’1x=-1: โˆ’4=โˆ’3A-4 = -3A, so A=43A = \frac{4}{3}.
  3. 3
    Result: 5x+1(x+1)(xโˆ’2)=4/3x+1+11/3xโˆ’2\frac{5x+1}{(x+1)(x-2)} = \frac{4/3}{x+1} + \frac{11/3}{x-2}.

Answer

5x+1(x+1)(xโˆ’2)=43(x+1)+113(xโˆ’2)\frac{5x+1}{(x+1)(x-2)} = \frac{4}{3(x+1)} + \frac{11}{3(x-2)}
Partial fraction decomposition splits a rational function into simpler fractions, each with a linear denominator. This decomposition is essential in integration and solving differential equations.

About Decomposition

The strategy of breaking a complex mathematical object or problem into simpler, independent subproblems that can be solved separately.

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