Curvature Intuition Math Example 4

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Example 4

hard
The osculating circle (circle of curvature) at a point on a curve has radius ฯ\rho. If the curvature at point PP is ฮบ=0.4\kappa = 0.4 cmโˆ’1^{-1}, find ฯ\rho. If the curvature doubles, what happens to ฯ\rho?

Solution

  1. 1
    Step 1: ฯ=1ฮบ=10.4=2.5\rho = \dfrac{1}{\kappa} = \dfrac{1}{0.4} = 2.5 cm.
  2. 2
    Step 2: If ฮบ\kappa doubles to 0.80.8 cmโˆ’1^{-1}, then ฯ=10.8=1.25\rho = \dfrac{1}{0.8} = 1.25 cm. The radius halves.

Answer

ฯ=2.5\rho = 2.5 cm; doubling curvature halves ฯ\rho to 1.251.25 cm.
The osculating circle at a point is the best-fitting circle to the curve at that point. Its radius ฯ=1/ฮบ\rho = 1/\kappa is inversely proportional to curvature. Doubling curvature halves the radius of curvature.

About Curvature Intuition

A measure of how quickly a curve bends or deviates from being a straight line at a given point.

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