Cube Roots Math Example 2

Solution

1. 1
   Factor $54$ to expose a perfect cube: $54 = 27 \times 2 = 3^3 \times 2$.
2. 2
   Split the cube root across the product: $\sqrt[3]{54} = \sqrt[3]{3^3 \times 2} = \sqrt[3]{3^3} \times \sqrt[3]{2}$.
3. 3
   Take the cube root of the perfect cube: $\sqrt[3]{3^3} = 3$, so the simplified form is $3\sqrt[3]{2}$.